So the formula for the volume of a sphere is 4/3 * (π * r³)

V = 4/3 * (π * 6³)

V = 4/3 * (π * 216)

V = 4/3 * 678.24

V = 904.78

I hope this helps! If it does, please rate as Brainliest :D

7 0

3 years ago

Johanna wrote the system of equations. 4 x - 3 y = 1, 5 x + 4 y = 9. If the second equation is multiplied by 4, what should the

polet [3.4K]

Answer:

The first equation must be multiplied by -5 to eliminate x variable by addition

Step-by-step explanation:

4 x - 3 y = 1 (1)

5 x + 4 y = 9 (2)

If the second equation is multiplied by 4

5x+4y=9. ×4

We have,

20x+16y=36 (3)

The first equation should be multiplied by -5 to eliminate x variable by addition

4x-3y=1 × -5

We have

-20x+15y=-5 (4)

Add equation (3) and (4) to eliminate x variable

20x+16y=36

-20x+15y=-5

31y=31

Divide both sides by 31

y=1

Substitute y=1 into equation (1)

4 x - 3 y = 1

4x-3(1)=1

4x-3=1

4x=1+3

4x=4

Divide both sides by 4

x=1

4 0

3 years ago

Read 2 more answers

Sequences:

joja [24]

Answer:

<u>The sequence is</u>

1, 1 + 2, 1 + 2 + 3, 1 + 2 + 3 + 4, ...

Each term is the sum of the consecutive numbers from 1 to that number.

<u>The nth term is the sum of the first n numbers:</u>

aₙ = 1 + 2 + 3 + ... + n
aₙ = 1/2n(1 + n) (formula for sum of the n terms of arithmetic progression with the first term of 1 and common difference of 1)
aₙ = n(n + 1)/2

1) The number of circles in the nth pile is n(n + 1)/2

2) When n tends to infinity the number of circles tends to infinity

4 0

3 years ago

The sum of two consecutive integers is 65. what are the two integers? show steps please.

Gnoma [55]

Hi student, let me help you out! :)

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

We are asked to find the two integers, given that they are consecutive, and their sum is 65.

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