A. 1,690 miles because it’s for 30 days and they do 12 miles each day
To calculate the remaining number of teams, use the sequence formula:
a(n) = a(1)Rⁿ-¹
Where a(n) and a(1) are the nth and first terms. R is the factor. Therefore, 24 teams is valid value.
After 5 rounds :
a(5) = 128*(½)⁴
a(5) = 128/16 = 8
8 teams are remained.
Answer:

Step-by-step explanation:
Sinse in this case you are dealing with direct variation, all you are doing is taking the <em>multiplicative</em><em> </em><em>inverse</em><em> </em>of 4, which is ¼:

This option is not an answer choise. Perhaps there was a typographical errour.
I am joyous to assist you at any time.
Answer:
Weights of at least 340.1 are in the highest 20%.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

a. Highest 20 percent
At least X
100-20 = 80
So X is the 80th percentile, which is X when Z has a pvalue of 0.8. So X when Z = 0.842.




Weights of at least 340.1 are in the highest 20%.