No sorry I hope you figure it out tho
Answer:
43.531
Step-by-step explanation:
This problem needs the law of cosines since the three sides of the triangle are involved as well as one angle. The law of cosines is:
c^2 = a^2 + b^2 - 2ab*cos(C)
Where the lowercase letters are side values and capital letters are angle values. Just in case I will mention side a is the one with a length of 14, side b is 20 and c = 12.
Since it is asking for angle A instead of angle C we can rewrite the law of cosines to fit that, basically just rearranging the letters.
a^2 = c^2 + b^2 - 2cb*cos(A)
Now we just plug in and solve.
14^2 = 12^2 + 20^2 - 2*12*20*cos(A)
Rearrange to get A by itself
![\frac{14^2-12^2-20^2}{-2*12*20}=cos(A)](https://tex.z-dn.net/?f=%5Cfrac%7B14%5E2-12%5E2-20%5E2%7D%7B-2%2A12%2A20%7D%3Dcos%28A%29)
Now we take the inverse cosine, or arccos of both sides to get our answer.
![arccos(\frac{14^2-12^2-20^2}{-2*12*20})=A](https://tex.z-dn.net/?f=arccos%28%5Cfrac%7B14%5E2-12%5E2-20%5E2%7D%7B-2%2A12%2A20%7D%29%3DA)
Let me know if there is something in my explanation you don't understand.
<span>The approximate area of the shaded region would be </span>47.25 cm.
Translate the given information into equations:
2L + 2W = 326
L = 2W - 5
Solve the system of equations.
2(2W - 5) + 2W = 326
4W - 10 + 2W = 326
6W - 10 = 326
6W = 336
W = 56
L = 2W - 5
L = 2(56) - 5
L = 107
Answer: Length: 107 ft; Width: 56 ft
Answer: Option B, x ≥ 121
Step-by-step explanation:
We start with the inequality:
√x ≥ 11.
First, we can square each side of the inequality, to get:
(√x)^2 ≥ 11^2
And we know that:
√(x^2) = (√x)^2 = x
Then:
x ≥ 11^2
x ≥ 121
So we only need to have x equal or larger than 121.
The correct option is B.