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3 years ago

Tutor me!

Mathematics

1 answer:

choli [55]3 years ago

8 0

Questions:

<h3><u>Let's start easy.</u></h3>

$5\frac{2}{3} -\frac{1}{4}$

<h3><u>Next up, let's make it a bit harder:</u></h3>

Ella is baking cookies to put in packages for a fundraiser. Ella has made 86 chocolate chip cookies and 42 sugar cookies.

Ella wants to create identical packages of cookies to sell, and she must use all of the cookies.

What is the greatest number of identical packages that Ella can make?

$\frac{17}{3} -\frac{1}{4}$

$\frac{17x4-3x 4 }{12} \\\\\frac{68-12}{12} \\\\\frac{56}{12} =\frac{28}{6}=\frac{14}{3}$

Multiply the denominators to make it one fraction.

Now for the numerator, you multiply the numerator of the the 1st fraction with the second fractions denominator. Then Multiply the 1st fractions denominator with the 2nd fractions numerator. Now with those two numbers you Subtract it. Whatever number you get is the numerator. So there is the fraction. You would just simplify it. (IF you want to add fractions instead of subtracting the numerators, you add the numerators. Like instead of 68-12 you would do 68+12

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write a function g whose graph represents a translation 2 units to the right followed by a horizontal stretch by a factor or 2 o

Alenkinab [10]

$\bf f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}\\\\
f(x)=&{{ A}} \left|{{ B }}x+{{ C}} \right|+{{ D}}
\\\\
--------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

with that template in mind, let's see,

$\bf f(x)=|x| \implies \begin{array}{lllccll}
f(x)=&1|&1x&+0|&+0\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}$

so, to shift it to the right by 2 units, simply set C = 2.
to stretch it by 2, set A = 1/2.

the smaller A is, the wider it opens, the larger it is, the more it shrinks.

5 0

3 years ago

PLS PLS PLS HELP 20 POINTS PLS HELP THX

Flura [38]

The first one- the rest don’t add up

8 0

2 years ago

The length of a rectangle is twice the width. If the perimeter of the rectangle is 60 units, find the area of the garden.

AlexFokin [52]

Perimeter = (length+width) x 2

Let w units be the width of the rectangle.

Length of the rectangle = 2w

Perimeter:
(2w+w) x 2 = 60

(3w)2 = 60

6w = 60

w = 10

Area:
2(10) x 10

= 20 x 10

= 200 units

4 0

2 years ago

Need help with this trigonometry word problem

kobusy [5.1K]

Answer:

86.6

Step-by-step explanation:

Here, AB represents height of the building, BC represents distance of the building from the point of observation.

In the right triangle ABC, the side which is opposite to the angle 60 degree is known as opposite side (AB), the side which is opposite to 90 degree is called hypotenuse side (AC) and the remaining side is called adjacent side (BC).

Now we need to find the length of the side AB.

tanθ = Opposite side/Adjacent side

tan 60° = AB/BC

√3 = AB/50

√3 x 50 = AB

AB = 50√3

Approximate value of √3 is 1.732

AB = 50 (1.732)

AB = 86.6 m

So, the height of the building is 86.6 m

4 0

3 years ago

Read 2 more answers

Plz help with this math. Can't find the area of the triangular faces.

Zina [86]

First of all, you have to find the area of both triangles:
$\frac{bh}{2}$
$\frac{4*4}{2}$
Or just 16 because there are 2 of the same triangles.

Now you have to find the area of the 3 rectangles.

The two that are in the front are 4*3 (l*h) or 12*2 (because there are 2 congruent rectangles. The area of those rectangles is 24 square mm.

Now you find the area of the back rectangle:
5.7*3 = 17.1

Finally, you add all the found numbers to figure out the surface area.
17.1 + 16 + 24 = 57.1 square millimeters.

Hope this helped,
Loafly

4 0

3 years ago