The measure of <ABD, <DBC and <ABC are 67, 67 and 134 degrees respectively.
<h3>Bisection of angles</h3>
Angles are bisected if they are divided into two equal parts.
If the angle BC bisects <ABC, hence <ABD and <DBC are equal, hence;
2(11x + 23) = <ABC
Given the following parameters
<ABC = 25x + 34
2(11x + 23) = 25x + 34
Expand
22x +46 = 25x + 34
22x-25x = 34 - 46
-3x = -12
x = 4
Determine the measure of the angles
<ABD = 11x + 23 = <DBC
<ABD = 11(4) + 23
<ABD = 44 + 23
<ABD = 67 degrees
<ABC = 2(67)
<ABC = 134 degrees
Hence the measure of <ABD, <DBC and <ABC are 67, 67 and 134 degrees respectively.
Learn more on bisection of angles here: brainly.com/question/25770607
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Answer:
Slope intercept form is y=mx+b
So y=-1/2x(m=slope which you go down one over 2 from your y-intercept)
y=-1/2x ( There would be no b because your b is 0, that's where it crosses the y axis)
Step-by-step explanation:
Answer:
19 square units
Step-by-step explanation:
Hello!
Step 1: Plot the points
We are first going to plot the points on the coordinate graph and connect the points to create a shape.
Refer to attachment titled "Step 1"
Step 2: Box the shape
Since this is an irregular shape, I'm going to make a box around the shape and subtract the area of the empty spaces to find the area of the original polygon.
Refer to attachment titled "Step 2"
Step 3: Area of Edges
We are going to find the area of the shapes A, B, and C and subtract them from the area of the big box to find the area of the polygon.
Area of a triangle = 1/2(base x height)
- Area of Box = 6 un x 7 un
- Area of Box = 42 un²
Area of A:
- Area A = 1/2(4 un x 2 un)
- Area A = 1/2(8 un²)
- Area A = 4 un²
Area of B:
- Area B = 4 un x 4 un
- Area B = 16 un²
Area of C:
- Area C = 1/2(2 un x 3 un)
- Area C = 1/2(6 un²)
- Area C = 3 un²
Step 4: Area of the polygon
Now, we can simply subtract the values of A, B, and C from the box to get the area of the polygon.
- Area Polygon = Box - A - B - C
- Area Polygon = 42 un² - 4 un² - 16 un² - 3 un²
- Area Polygon = 38 un² - 16 un² - 3 un²
- Area Polygon = 22 un² - 3 un²
- Area Polygon = 19 un²
The area of the polygon is 19 un²
-Chetan K