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3 years ago

What is the 33rd term of this arithmetic sequence? 12, 7, 2, -3, -8, …

Mathematics

1 answer:

sergiy2304 [10]3 years ago

7 0

The answer be negative 158 or -158

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3 years ago

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mote1985 [20]

Answer:

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Step-by-step explanation:

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3 years ago

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The water from a fire hose follows a path described by y equals 2.0 plus 0.9 x minus 0.10 x squared (units are in meters). If

Alecsey [184]

Answer:

The resultant velocity is 12.21 m/s.

Step-by-step explanation:

We are given that the water from a fire hose follows a path described by y equals 2.0 plus 0.9 x minus 0.10 x squared (units are in meters).

Also, v Subscript x is constant at 10.0 m/s.

The water from a fire hose follows a path described by the following equation below;

$y=2.0 + 0.9x-0.10x^{2}$

The velocity of the $x$ component is constant at = $v_x=10.0 \text{ m/s}$

and the point at which resultant velocity has to be calculated is (9.0,2.0).

Let the velocity of x and y component be represented as;

$v_x=\frac{dx}{dt} \text{ and } v_y=\frac{dy}{dt}$

Now, differentiating the above equation with respect to t, we get;

$y=2.0 + 0.9x-0.10x^{2}$

$\frac{dy}{dt} =0 + 0.9\frac{dx}{dt} -(0.10\times 2)\frac{dx}{dt}$

$\frac{dy}{dt} = 0.9\frac{dx}{dt} -0.2\frac{dx}{dt}$

$v_y = 0.9v_x -0.2v_x$

$v_y = 0.7v_x$

Now, putting $v_x=10.0 \text{ m/s}$ in the above equation;

$v_y = 0.7 \times 10.0$ = 7 m/s

Now, the resultant velocity is given by = $v=\sqrt{v_x^{2}+v_y^{2} }$

$v=\sqrt{10^{2}+7^{2} }$

= $\sqrt{149}$ = 12.21 m/s

5 0

3 years ago

Item 7 You run for 2 hours at a speed no faster than 6.3 miles per hour.Question 1 Write an inequality that represents the possi

aalyn [17]

The formula which relates Distance, av.Speed and Time is
$Distance=Speed\cdot Time$

The maximal Distance would be covered if the average speed was 6.3 miles per hour.

In that case D=6.3 (mi/h) * 2 h = 12.6 mi

thus, if x represents the number of miles, x≤12.6 mi

Answer: x≤12.6 mi

3 0

4 years ago