I don't know.. what happens next?
RST is not a right triangle.
<h3>What is a Triangle ?</h3>
A Triangle is a polygon with three sides , three angles and three vertices.
It is given in the question that
triangle RST with coordinates R(2, 3), S(4, 4), and T(5, 0)
It has to be determined that if the triangle is a right angled triangle ,
If we plot the triangle on the coordinate plane , it can be easily seen that the triangle is not a right angled triangle ,
It can also be proved by measuring the length of the sides that if the sum of the squares of the sides is equal to the square of the largest side , then it will be a right triangle or not .
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The Formula's for a cylinder is V=
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r^2h and the volume of a Cone is V=1/3
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r^2h. So you would know that the volume of a cone is 1/3 the volume of a cylinder.
(-3,3] is an interval which means that -3 and 3 are not inclusive of the values of x -5/3.
We have given
-3x+4 > 9
Required values of x.
State the values of x within -3 and 3.
subtract 4 from both sides,
-3x+4-4>9-4
<h3>What is the meaning of like terms?</h3>
like terms are terms that have the same variables and powers. The coefficients do not need to match.
Collect Like Terms
-3x > 5
(-3x)(-1) < 5(-1)
3x < -5
Divide both sides by 3
3x/3 < -5/3
x < -5/3
(-3,3] is an interval which means that -3 and 3 are not inclusive of the values of x is -5/3.
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Answer:
Step-by-step explanation:
Perhaps you want to use the points (t, P) = (4, 150) and (6, 160) to find the parameters P0 and k in the equation ...
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We know from the given points that we can write the equation as ...

Comparing this to the desired form, we see that ...

So, the approximate equation for P is ...
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And the parameters of interest are ...