Answer:
7 1/3
Step-by-step explanation:
V = πr²h
V₁ = π x 4² x 11 = 176π
v₂ = π x 2² x 6 = 24π
V₁ /v₂ = 176π / 24π = 22/3 = 7 1/3
Answer:
Step-by-step explanation:
First, look at the graph to determine whether it opens down or up, which in this case is <em>down</em>, so you insert a negative in front of the expression. Next, locate your <em>x-intercepts</em> [<em>zeros</em> (where the graph insects the x-axis)]. You will see that the graph intersects ![\displaystyle [-2, 0]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5B-2%2C%200%5D)
and ![\displaystyle [4, 0],](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5B4%2C%200%5D%2C)
so what you do is insert the zeros' OPPOCITES into the equation because according to the vertex equation, ![\displaystyle y = A[x - h]^2 + k,](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%20%3D%20A%5Bx%20-%20h%5D%5E2%20%2B%20k%2C)
that negative in front of 
gives you the OPPOCITE outcome, so be careful.
I am joyous to assist you at any time.
Completing the Square
2. Solve the equation by completing the square. Show your work.
x^2 – 30x = –125
Step 1: Add to both sides of the equation. (2 points)
Add 225 both sides of the equation
x^2 – 30x + 225 = –125
+ 225
x^2 - 30x + 225 = 100
Step 2: Factor the left side of the equation. Show your work. (2 points)
Hint: It is a perfect square trinomial.
x^2 - 30x + 225 = 100
Factor the left side of the equation:
(x - 15)^2 = 100
Step 3: Take the square root of both sides of the equation from Step 2. (1 point)
√(x - 15)^2 = √100
Step 4: Simplify the radical and solve for x. Show your work. (1 point)
x - 15 = + - 10
x - 15 = 10
x = 25
x - 15 = -10
x = 5
Solutions x = 25, 5
Answer:
290
Step-by-step explanation:
Surface area=2(wl+hl+hw), 2(25+60+60), 145*2, 290
Answer:
Step-by-step explanation:
this quotient is:
d
------------
(-1/4)
Then:
d
------------ < -3/2
(-1/4)
You weren't asked to solve this. But if you wish to do so:
-4d < -3/2
Multiplying both sides by 2, to eliminate the fraction:
-8d < -3
Dividing both sides by -8, we get d > 3/8. We must change the direction of the original inequality sign.
