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3 years ago

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Suppose you invest $2000 at an annual interest rate of 4.5%. how long will it take for it to earn $495?

1 answer:

Neko [114]3 years ago

3 0

100%:2000$=4.5%:x$, x=90$. After 1st year I earned 90$, now I have 2090$.
100%:2090$=4.5%:x$, x=94.5$. After 2nd year I earned 94.5$ more, now I have 2184.05$.
100%:2184.05$=4.5%:x$, x=98.28$. After 3rd year I have 2282.33$.
100%:2282.33$=4.5%:x$, x=102.71$. After 4th year I have 2385.04$.
100%:2385.04$=4.5%:x$, x=107.33$. After 5th year I have 2492.37$.

So I need 6 years to earn 495$.

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NEED HELP WITH THESE QUESTIONS

amm1812

For this case we must solve the following questions:

Question 1:

We should simplify the following expression:

$\frac {\frac {m ^ 2 * n ^ 3} {p ^ 3}} {\frac {mp} {n ^ 2}} =$

Applying double C we have:

$\frac {m ^ 2 * n ^ 3 * n ^ 2} {mp * p ^ 3} =$

By definition of multiplication of powers of the same base we have to place the same base and add the exponents: $\frac {m ^ 2 * n ^ 5} {m * p ^ 4} =$

Canceling common terms:

$\frac {mn ^ 5} {p ^ 4}$

Answer:

Option A

Question 2:

We should simplify the following expression:

$\frac {3xyz ^ 2} {6y ^ 4} * \frac {2y} {xz ^ 4}$

So, we have:

$\frac {3xyz ^ 2 * 2y} {6y ^ 4 * xz ^ 4} =\\\frac {6xy ^ 2z ^ 2} {6y ^ 4xz ^ 4} =$

Simplifying common terms:

$\frac {1} {y ^ 2z ^ 2}$

Answer:

Option D

Question 3:

We factor the following expressions to rewrite the experience:

<em> $r ^ 2 + 7r + 10$ : </em>We look for two numbers that multiplied give 10 and added 7:

$(r + 5) (r + 2)$

<em> $r ^ 2-5r-50:$ </em> We look for two numbers that multiplied give -50 and added -5:

$(r-10) (r + 5)$

<em> $3r-30 = 3 (r-10)$ </em>

Rewriting the given expression we have:

$\frac {(r + 5) (r + 2) * 3 (r-10)} {3 (r-10) (r + 5)} =$

We simplify common terms in the numerator and denominator we have:

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Answer:

Option D

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Find the sum. <br> Homework: 9.4 arithmetic series

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Step-by-step explanation:

a1 = 3(1) - 7 = - 4

a2 = 3(2) - 7 = -1

d = a2 - a1

d = -1 - (-4)

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d = 3

a60 = 3(60) - 7

a60 = 180 - 7

a60 = 173

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Sum = (a1 + a60) * n / 2

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Sum = (169)*30

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==================

Just to check, we'll use the second summation formula

d = 3

n = 60

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Sum = (2*a1 + (n - 1)*d )*n / 2

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Same answer.

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