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nasty-shy [4]
3 years ago
13

Can someone help me so stressed 29 points Thanks

Mathematics
1 answer:
GenaCL600 [577]3 years ago
7 0

Answer:a square

Step-by-step explanation:a square

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Simplify 5(a - <br> b. 6(a <br> b. - 7(a - 2b)
Elan Coil [88]
Not sure what you're asking. are you wanting to solve 5 ( a - b), where b equals those two things listed below? If that's the case, I can definitely help. If not, please clarify.
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4 years ago
Can someone fr help me with this like right now i’ll appreciate it sm
rjkz [21]

Step-by-step explanation:

Since

\frac{108}{72}  =  \frac{3}{2}

\frac{72}{48}  =  \frac{3}{2}

\frac{48}{32}  =  \frac{3}{2}

The function has a constant factor so we have a exponential function.

The equation of a exponential function is

y = a(b) {}^{x}

Where a is the initial value and b is the growth factor

The growth factor is 3/2,

The initial value in 32

y =  32 ( \frac{3}{2} ) {}^{x}

Plug in 4 for x.

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Plug in 5 for x you will get

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2013- 162

2014- 243

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VMariaS [17]

Answer:

The answer is the last option/diamond

Step-by-step explanation:

6 0
4 years ago
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skelet666 [1.2K]

Answer:

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5 0
3 years ago
Read 2 more answers
divide the number 60 into 2 parts so that if one part is divided by 6 and the other part is divided by 8 the sum of the answer w
konstantin123 [22]
If we divide  60 into say hmmm two integers, and those integers are say "a" and "b", then  a + b = 60, therefore, a = 60 - b.

\bf \stackrel{\textit{one part is divided by 6}}{\cfrac{a}{6}}~~+~~\stackrel{\textit{the other part is divided by 8}}{\cfrac{b}{8}}~~=~~9&#10;\\\\\\&#10;\cfrac{60-b}{6}~~+~~\cfrac{b}{8}=9\impliedby &#10;\begin{array}{llll}&#10;\textit{let's multiply both sides by}\\&#10;\textit{the LCD of 24}&#10;\end{array}&#10;\\\\\\&#10;24\left( \cfrac{60-b}{6}~~+~~\cfrac{b}{8} \right)=24(9)\implies 240-4b+3b=216&#10;\\\\\\&#10;-b=-24\implies b=\cfrac{-24}{-1}\implies b=24

what's the first integer?  well, a = 60 - b.
5 0
3 years ago
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