In a comluter game a bird flies 1,281 feet in the air, while a fish swims 282 feet below sea level what is the difference

. A man bought a car for $60 320. After using it for 2 years he decides to trade in the car. The company estimated a depreciatio

Veronika [31]

Answer:

(a) 39,208

(b) 65%

Step-by-step explanation:

(a) The car loses 10% the first year and 15% the second year so that’s 35% lost in total after two years.

35% of 60,320 is 21,112

60,320 - 21,112 = 39,208

39,208 ÷ 60,320 = 0.65 (65%)

8 0

2 years ago

The number of people arriving at a ballpark is random, with a Poisson distributed arrival. If the mean number of arrivals is 10,

Stella [2.4K]

Answer:

a) 3.47% probability that there will be exactly 15 arrivals.

b) 58.31% probability that there are no more than 10 arrivals.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

If the mean number of arrivals is 10

This means that $\mu = 10$

(a) that there will be exactly 15 arrivals?

This is P(X = 15). So

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 15) = \frac{e^{-10}*(10)^{15}}{(15)!} = 0.0347$

3.47% probability that there will be exactly 15 arrivals.

(b) no more than 10 arrivals?

This is $P(X \leq 10)$

$P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-10}*(10)^{0}}{(0)!} = 0.000045$

$P(X = 1) = \frac{e^{-10}*(10)^{1}}{(1)!} = 0.00045$

$P(X = 2) = \frac{e^{-10}*(10)^{2}}{(2)!} = 0.0023$

$P(X = 3) = \frac{e^{-10}*(10)^{3}}{(3)!} = 0.0076$

$P(X = 4) = \frac{e^{-10}*(10)^{4}}{(4)!} = 0.0189$

$P(X = 5) = \frac{e^{-10}*(10)^{5}}{(5)!} = 0.0378$

$P(X = 6) = \frac{e^{-10}*(10)^{6}}{(6)!} = 0.0631$

$P(X = 7) = \frac{e^{-10}*(10)^{7}}{(7)!} = 0.0901$

$P(X = 8) = \frac{e^{-10}*(10)^{8}}{(8)!} = 0.1126$

$P(X = 9) = \frac{e^{-10}*(10)^{9}}{(9)!} = 0.1251$

$P(X = 10) = \frac{e^{-10}*(10)^{10}}{(10)!} = 0.1251$

$P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.000045 + 0.00045 + 0.0023 + 0.0076 + 0.0189 + 0.0378 + 0.0631 + 0.0901 + 0.1126 + 0.1251 + 0.1251 = 0.5831$

58.31% probability that there are no more than 10 arrivals.

8 0

3 years ago

Solve for a: am=n+p <br><br> Help me

ss7ja [257]

Answer:

a = (n + p)/m

Step-by-step explanation:

just divide by m on both sides

hope this helped!

6 0

3 years ago

What are the intercepts of y=4x-2?

pshichka [43]

First, solve for the x - intercept. To do so, equate y to 0 and solve for x.

0 = 4x - 2, x = 1/2

Second, solve for the y - intercept. Equate x to 0 which will give us,

y = (4)(0) -2, y = -2

Therefore, the x-intercept is 1/2 and y-intercept is -2.

8 0

3 years ago

. Which numbers are all divisible by 5? 1. 124, 333, 315, 266, 391 2. 135, 205, 330, 275, 365 3. 135, 211, 330, 274, 252 4. 232,

Ad libitum [116K]

Any numbers are ending with 5 and 0 can divide by 5
so answer:
<span>2. 135, 205, 330, 275, 365</span>

6 0

3 years ago

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