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Andru [333]
2 years ago
8

154 pm is greater than 7.7 x10^-9 A. True B. False

Chemistry
1 answer:
Nesterboy [21]2 years ago
7 0
The answer is false.
You might be interested in
An experiment reveals that 125.0 grams of an unknown metal increases in temperature from 22.0 oC to 43.6 oC upon absorbing 640 j
nydimaria [60]

Answer:

                     Cp  =  0.237 J.g⁻¹.°C⁻¹

Explanation:

                      Amount of energy required by known amount of a substance to raise its temperature by one degree is called specific heat capacity.

The equation used for this problem is as follow,

                                                 Q  =  m Cp ΔT   ----- (1)

Where;

           Q  =  Heat  =  640 J

           m  =  mass  =  125 g

           Cp  =  Specific Heat Capacity  =  <u>??</u>

           ΔT  =  Change in Temperature  =  43.6 °C  -  22 °C  =  21.6 °C

Solving eq. 1 for Cp,

                                Cp  =  Q / m ΔT

Putting values,

                                Cp  =  640 J / (125 g × 21.6 °C)

                                Cp  =  0.237 J.g⁻¹.°C⁻¹

3 0
3 years ago
What are some properties of matter that can be identified without testing or measuring
kiruha [24]
Physical change - No change of matter in this phase
chemical change - All types of phase change occur here
8 0
3 years ago
What is the definition of a Lewis acid?
Sveta_85 [38]

Answer:

A Lewis acid is a chemical species that contains an empty orbital which is capable of accepting an electron pair from a Lewis base to form a Lewis adduct

Explanation:

CAN YOU MAKE ME BRAINELIST PLEASE

8 0
3 years ago
0.415 g of an unknown triprotic acid are used to make a 100.00 mL solution. Then 25.00 mL of this solution is transferred to an
Arturiano [62]

Answer:

Explanation:

Initial burette reading = 1.81 mL

final burette reading = 39.7 mL

volume of NaOH used = 39.7 - 1.81 = 37.89 mL .  

37.89 mL of .1029 M NaOH is used to neutralise triprotic acid

No of moles contained by 37.89 mL of .1029 M NaOH

= .03789 x .1029 moles

= 3.89 x 10⁻³ moles

Since acid is triprotic ,  its equivalent weight = molecular weight / 3

No of moles of triprotic acid = 3.89 x 10⁻³ / 3

= 1.30   x 10⁻³ moles .

8 0
3 years ago
38 points!! &gt;:D
Sav [38]

Answer: which*

Explanation:

8 0
3 years ago
Read 2 more answers
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