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Llana [10]
3 years ago
15

There are several hazards associated with the chemicals in the qualitative analysis experiment. for each chemical, identify the

associated hazards. (select all that apply.) hazard 0.1 m ag+ 0.1 m ba2+ 0.1 m fe3+ 6 m hcl 6 m h2so4 6 m hno3 7.5 m nh3 corrosive irritating vapors toxic if ingested causes staining on skin flammable none listed
Chemistry
1 answer:
Ilia_Sergeevich [38]3 years ago
7 0
You can determine the hazards of these chemicals by looking at their material data safety sheets (MSDS). 

1. 0.1 M Ag⁺: Silver compounds are absorbed by skin causing bluish pigmentation. Thus, it <em>causes </em><span><em>staining on skin</em>.</span> Also, liquid <em>vapor may be irritating</em> to skin and also <em>moderately toxic when ingested</em>.

2. 0.1 M Ba²⁺: This is <em>mildly toxic when ingested</em> causing stomach irritation, muscle weakness, swelling of organs like brain, liver, kidney and heart.

3. 0.1 M Fe³⁺:Iron is <em>corrosive, has irritating vapor especially to the eyes, and toxic if ingested</em>.

4. 6 M HCl: This is a concentrated strong acid, so it is <em>corrosive, has irritating vapors, flammable and toxic when ingested</em>.

5. 6 M H₂SO₄: This is also a concentrated strong acid. Moreover, it is a strong oxidizing agent. So, its hazards include: <span><em>corrosive, has irritating vapors, toxic when ingested and causes staining on skin</em>.

</span>
6. 6 M HNO₃: This is a concentrated strong acid, so it is <em>corrosive, has irritating vapors, flammable and toxic when ingested</em>.

7. 7.5 M NH₃: This is a weak base. It is characterized for its pungent odor. This is <em>corrosive, has irritating vapors, toxic if ingested, and flammable</em>.
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They can still be effected it large quantities of soap are added to water

because more soap eliminates the effect the minerals in hard water has on

its cleaning capacity.

Hard water contains minerals such as

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They reduce the cleaning capacity of the soap. This is why soft water is

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2 years ago
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Chlorine released from chlorofluorocarbons (cfcs) reacts with ozone in the atmosphere to form oxygen. the proposed reactions are
lara [203]
The catalyst is what appears exactly the same at the end and appears early in the equation set. In this case Cl(g).The intermediate appears "intermediately" not at the beginning or at the end, but is made and consumed in the middle. Like ClO(g). A substance that is regenerated in the next is a catalyst and is consumed in the first step. In contrast, when a substance is formed in the first step and is consumed in the next step, then it is known as an intermediate.
5 0
3 years ago
A gas has a volume of 5.00 L at 0°C. What final temperature, in degrees Celsius, is needed to change the volume of the gas to ea
Diano4ka-milaya [45]

Answer:

A = -213.09°C

B = 15014.85 °C

C = -268.37°C

Explanation:

Given data:

Initial volume of gas = 5.00 L

Initial temperature = 0°C  (273 K)

Final volume = 1100 mL, 280 L, 87.5 mL

Final temperature = ?

Solution:

Formula:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Conversion of mL into L.

Final volume = 1100 mL/1000 = 1.1 L

Final volume =  87.5 mL/1000 = 0.0875 L

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂ = V₂T₁ / V₁

T₂ = 1.1 L × 273 K / 5.00 L

T₂ = 300.3 L.K / 5.00 K

T₂ = 60.06 K

60.06 K - 273 = -213.09°C

2)

V₁/T₁ = V₂/T₂

T₂ = V₂T₁ / V₁

T₂ = 280 L × 273 K / 5.00 L

T₂ = 76440 L.K / 5.00 K

T₂ = 15288 K

15288 K - 273 = 15014.85 °C

3)

V₁/T₁ = V₂/T₂

T₂ = V₂T₁ / V₁

T₂ = 0.0875 L × 273 K / 5.00 L

T₂ = 23.8875 L.K / 5.00 K

T₂ = 4.78 K

4.78 K - 273 = -268.37°C

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Bromine (Br) belongs to the halogen family. Based on the location of the halogens, how many valence electrons does bromine have?
Amanda [17]

Answer:

D. 7

Explanation:

The halogens are found in Group 7 of the Periodic Table. If Bromine is a halogen, then that means it would be found in Group 7. Also, elements in Group 7 have 7 electrons in its outer shell, Bromine would have 7 electrons in its outer shell.

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