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-Dominant- [34]
3 years ago
10

Jada had some dimes and quarters that had a total value of $12.50. The relationship between the number of dimes, d, and the numb

er of quarters, q, can be expressed by the equation
01.d + 0.25q = 12.5.
1. If Jada has 4 quarters, how many dimes does she have?
2. If Jada has 10 quarters, how many dimes does she have?
3. Is the number of dimes a function of the number of quarters? If yes, write a rule (that starts with d =...) that you can use to determine the output, d, from a given input, q. If no, explain why not.
Mathematics
2 answers:
podryga [215]3 years ago
4 0
Hi! This might be long but I hope it helps!

1. 115. If q=4, then the equation tells us that 0.1d+(0.25)⋅4=12.5. Subtracting 1 from both sides gives 0.1d=11.5, so d=115.

2. 100. If q=10, then the equation tells us that 0.1d+(0.25)⋅10=12.5. Subtracting 2.5 from both sides gives 0.1d=10, so d=100.

3. Yes. If you know the number of quarters, then you can determine the number of dimes from the equation. We can even write the equation in a way that shows this: d=125−2.5q. The expression 125−2.5qrepresents the output—it is the rule that determines the output d from a given input q.
Crank3 years ago
3 0

Answer:

1. 115. If q=4, then the equation tells us that 0.1d+(0.25)⋅4=12.5. Subtracting 1 from both sides gives 0.1d=11.5, so d=115.

2. 100. If q=10, then the equation tells us that 0.1d+(0.25)⋅10=12.5. Subtracting 2.5 from both sides gives 0.1d=10, so d=100.

3. Yes. If you know the number of quarters, then you can determine the number of dimes from the equation. We can even write the equation in a way that shows this: d=125−2.5q. The expression 125−2.5qrepresents the output—it is the rule that determines the output d from a given input q.

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Answer:

Eight times ten plus six times one plus two times one-tenth plus seven times one-thousandth.

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4 0
2 years ago
On which interval is the average rate of change for bicycle production the greatest? A) 1950 to 1960 B) 1960 to 1970 C) 1970 to
Alborosie

Answer:

D) 1980 to 2000

Step-by-step explanation:

Finding the average rate of change in each interval to determine the greatest one.

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Rate of change (1960-1970) = \frac{20}{21} \times 100= 95.23\%

Rate of change (1970-1980)=  \frac{30}{41} \times 100= 73.17\%

Rate of change (1980-2000)= \frac{90}{71} \times 100= 126.76\%

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Dear Student,

Answer to your query is provided below:

The length of segment AB = 8

Explanation to answer is provided by attaching image.

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