Let's say the first number is "a"
the next consecutive can just be "a+1" and the next, you guessed it, "a+2"
the two smaller ones are a and a+1, the larger one is a+2
now, the product of "a" and "a+1" equals 5 times "a+2" but less by 5
thus a(a + 1) = 5(a + 2) - 5 <----- solve for "a"
Answer:
let required no be x
by doing crisscrossed multiplication
42=7x
dividing both side by 7
6=x
therefore x=6
therefore value of remaining no.is 6
Answer:
23 and 33
Step-by-step explanation:
23+33=56
33-23=10
Answer:
X = -5
Step-by-step explanation:
-6x + 18 = 7 - (4x + 9)
first we simplify the parentheses.
distribute the invisible number one created by the negative sign in front of the parentheses to get -6x + 18 = 7 - 4x - 9
then simplify further by subtracting 9 from the right side, leaving you with
-6x + 18 = -2 - 4x
next, add 2 to both sides to isolate the variable.
-6x + 20 = -4x
then, to isolate the variable further add 6x to both sides.
20 = -4x
divide both sides by -4 to isolate the variable
-5 = x
so, x = -5
Answer:
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