Television sizes are labeled by the measure of the diagonal. What size is the TV below?

Mathematics

1 answer:

alukav5142 [94]2 years ago

6 0

Answer:

55 inches.

Step-by-step explanation:

So, in the question above we are given the following data or parameters or information which will assist us in solving this kind of question efficiently. Here are the information needed below;

(1). "Television sizes are labeled by the measure of the diagonal.''

(2). "47.5 inches up top and the side is 27 inches" which are the length and the breadth respectively. Therefore, we will make use of the formula below In solving this question;

Size of the Television = √[(Length of the Television)^2 × (breadth of the television)^2].

Hence, the size of the Television = √( 47.5)^2 + (27)^2. = 54.63744137494.

Approximately:

The Size of the Television = 55 inches.

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This is the same as saying $6i\sqrt{5}$

====================================================

Work Shown:

$\sqrt{-180} = \sqrt{-1*36*5}\\\\\sqrt{-180} = \sqrt{-1}*\sqrt{36}*\sqrt{5}\\\\\sqrt{-180} = i*6*\sqrt{5}\\\\\sqrt{-180} = 6i\sqrt{5}\\\\\sqrt{-180} = (6\sqrt{5})i\\\\$

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As the steps show above, the idea is to factor the radicand into smaller pieces where one of those pieces is the largest perfect square possible. In this case, 36 is the largest factor of 180 that's a perfect square. Then I used the rule $\sqrt{A*B} = \sqrt{A}*\sqrt{B}$ to break up the root.