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Rudik [331]
3 years ago
7

Given the quadratic relation y = -x2 + 6x - 6, a) write the equation in vertex form b) graph the quadratic relation (using noteb

ook, Google Drawings, or by hand) using transformations on y = x2. Insert your graph image (or link) here.
I am pretty sure that for this one vertex form is -(x-3)^2+3
Double check that answer and then graph it please!

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
8 0
<h3>Answer:</h3>
  • y = -(x -3)² +3 . . . . (agrees with your answer)
  • see the attachment for a graph
<h3>Step-by-step explanation:</h3>

Factoring the leading -1 from the first two terms, we have ...

... y = -(x² -6x) -6

Adding 9 inside parentheses to complete the square, then adding the opposite amount outside parentheses, we have ...

... y = -(x² -6x +9) -6 +9

... y = -(x -3)² +3

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3 years ago
what is the slope of the line through (1,0)(1,0)left parenthesis, 1, comma, 0, right parenthesis and (3,8)(3,8)
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The slope of the line passing through (1 , 0) and (3 , 8) is 4.

Slope, commonly represented by the letter m, is a value that describes the steepness and direction of a line. The slope of a line is also called its gradient or rate of change.

It is the vertical change in y divided by the horizontal change in x, sometimes called rise over run. The slope formula uses two points, (x_{1}, y_{1} ) and (x_{2}, y_{2} ), to calculate the change in y over the change in x.

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7 0
2 years ago
PLEASE HELP! I'll give 5 out of 5 stars, give thanks, and give as many points as I can.
Liula [17]

Answer:

\boxed{\boxed{x=\dfrac{\pi}{3}\ \vee\ x=\pi\ \vee\ x=\dfrac{5\pi}{3}}}

Step-by-step explanation:

\cos(3x)=-1\iff3x=\pi+2k\pi\qquad k\in\mathbb{Z}\\\\\text{divide both sides by 3}\\\\x=\dfrac{\pi}{3}+\dfrac{2k\pi}{3}\\\\x\in[0,\ 2\pi)

\text{for}\ k=0\to x=\dfrac{\pi}{3}+\dfrac{2(0)\pi}{3}=\dfrac{\pi}{3}+0=\boxed{\dfrac{\pi}{3}}\in[0,\ 2\pi)\\\\\text{for}\ k=1\to x=\dfrac{\pi}{3}+\dfrac{2(1)\pi}{3}=\dfrac{\pi}{3}+\dfrac{2\pi}{3}=\dfrac{3\pi}{3}=\boxed{\pi}\in[0,\ 2\pi)\\\\\text{for}\ k=2\to x=\dfrac{\pi}{3}+\dfrac{2(2)\pi}{3}=\dfrac{\pi}{3}+\dfrac{4\pi}{3}=\boxed{\dfrac{5\pi}{3}}\in[0,\ 2\pi)\\\\\text{for}\ k=3\to x=\dfrac{\pi}{3}+\dfrac{2(3)\pi}{3}=\dfrac{\pi}{3}+\dfrac{6\pi}{3}=\dfrac{7\pi}{3}\notin[0,\ 2\po)

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3 years ago
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