At Avery Middle School, 273 students responded to a survey asking whether a Bulldog, a Lion, or a Tiger should be the new school
2 answers:
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Answer:
Height of plane = 25971.7 meters
Step-by-step explanation:
let H =height of plane
Let x = distance ray to the point under the plane
800 foot = 245meters
1 mile = 1609meters.
Tan 81 = -----------------------(1)
Tan 67 = -----------------------(2)
6.3134 = ------------------------(3)
2.3556 = -----------------------(4)
from (3) and (4)
H = 10158.26 + 6.3134x ---------------(a)
H = 245 + 2.2336x ---------------(b)
equating both (a) and (b) we have:
9913.26 = 3.9576x
x = 2504.74
Subst. x = 2504.74 into (a)
H = 25971.7meters
<em>Acceleration (a) = 5.1 m/s</em>²
<em>Initial speed (u) = 16 km/h </em>⇒
<em>m/s </em>≈ <em>4.5m/s</em><em>
</em><em>Final speed (v) =118 km/h </em>⇒
<em>m/s</em> ≈ <em>32.8m/s</em><em>
</em>
Distance(S) travel in that particular instant is carried out by 'Third equation of motion' i.e., v² = u² + 2aS
<em>So, When all quantities are in S.I. unit then,
</em>putting the values in the equation of motion,
<em /><em>As we have to carry out the distance covered,
</em><em>2</em>·<em>a</em>·<em>S = v</em>² <em>- u</em>²
<em>S = </em>
Putting values in derived equation,
⇒ <em>S = </em>
⇒ <em>S = </em>
⇒ <em>S = </em>
⇒ <em>S </em>≈ <em>103.489</em> <em>m
</em><em>
The total distance covered in that given condition is approx. 103.289 m.</em>
<em>Initial speed (u) = 16 km/h </em>⇒
</em><em>Final speed (v) =118 km/h </em>⇒
</em>
Distance(S) travel in that particular instant is carried out by 'Third equation of motion' i.e., v² = u² + 2aS
<em>So, When all quantities are in S.I. unit then,
</em>putting the values in the equation of motion,
<em /><em>As we have to carry out the distance covered,
</em><em>2</em>·<em>a</em>·<em>S = v</em>² <em>- u</em>²
<em>S = </em>
Putting values in derived equation,
⇒ <em>S = </em>
⇒ <em>S = </em>
⇒ <em>S = </em>
⇒ <em>S </em>≈ <em>103.489</em> <em>m
</em><em>
The total distance covered in that given condition is approx. 103.289 m.</em>