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3 years ago

3. Suppose that the interior angles of a convex hexagon are six

Mathematics

1 answer:

juin [17]3 years ago

5 0

Answer:

The largest angle is A + 5 = 117.5 + 5 = 122.5 degree.

Step-by-step explanation:

The sum of the interior angles of a regular hexagon is 720 degree.

Let the one angle is A.

So,

A + A + 1 + A + 2 + A + 3 + A + 4 + A + 5 = 720

6 A + 15 = 720

6 A = 705

A = 117.5

The largest angle is A + 5 = 117.5 + 5 = 122.5 degree.

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What's the answer for 24

scZoUnD [109]

X= -2 or X= 3 either one works.

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3 years ago

Number 7 and 8 plz answer quickly

Flauer [41]

(7) m∠A = 52°

(8) m∠B = 117°

Solution:

(7) Let us first define the supplementary and complementary angles.

Supplementary angles: Two angles are said to be supplementary angles if their sum is add up to 180°

Complementary angles: Two angles are said to be complementary angles if their sum is add up to 90°

Given supplement of 142° = 180° – 142°

= 38°

Complement of ∠A = Supplement of 142°

⇒ Complement of ∠A = 38°

Measure of ∠A = 90° – 38°

= 52°

Hence m∠A = 52°.

(8) Given complement of 27° = 90° – 27°

= 63°

Supplement of ∠B = Complement of 27°

⇒ Supplement of ∠B = 63°

Measure of ∠B = 180° – 63°

= 117°

Hence m∠B = 117°.

3 0

4 years ago

Math question plz help

Svetach [21]

Answer:

Yes they are.

Because:

As said in the rules you have to keep the bases and add the exponents.

7 0

3 years ago

Read 2 more answers

The manager of a computer retails store is concerned that his suppliers have been giving him laptop computers with lower than av

34kurt

Answer:

Probability that the 50 randomly selected laptops will have a mean replacement time of 3.1 years or less is 0.0092.

Yes. The probability of this data is unlikely to have occurred by chance alone.

Step-by-step explanation:

We are given that the replacement times for the model laptop of concern are normally distributed with a mean of 3.3 years and a standard deviation of 0.6 years.

He then randomly selects records on 50 laptops sold in the past and finds that the mean replacement time is 3.1 years.

<em>Let M = sample mean replacement time</em>

The z-score probability distribution for sample mean is given by;

Z = $\frac{ M-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ ~ N(0,1)

where, $\mu$ = population mean replacement time = 3.3 years

$\sigma$ = standard deviation = 0.6 years

n = sample of laptops = 50

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the 50 randomly selected laptops will have a mean replacement time of 3.1 years or less is given by = P(M $\leq$ 3.1 years)

P(M $\leq$ 3.1 years) = P( $\frac{ M-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ $\leq$ $\frac{ 3.1-3.3}{\frac{0.6}{\sqrt{50} } }} }$ ) = P(Z $\leq$ -2.357) = 1 - P(Z $\leq$ 2.357)

= 1 - 0.99078 = <u>0.0092</u> or 0.92%

<em>So, in the z table the P(Z </em> $\leq$ <em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2.357 in the z table which will lie between x = 2.35 and x = 2.36 which has an area of 0.99078.</em>

Hence, the required probability is 0.0092 or 0.92%.

Now, based on the result above; <u>Yes, the computer store has been given laptops of lower than average quality</u> because the probability of this data is unlikely to have occurred by chance alone as the probability of happening the given event is very low as 0.92%.

8 0

3 years ago

Perimeter, Area And Volume

Maslowich

$\large\huge\green{\sf{Answer:-}}$

<h3>area of shaded figure= </h3>

<h2>area of whole rectangle</h2>

= lengthx breadth=15x30= 450 cm²

<h3>area of unshaded region= lengthx breadth= (30-8)x 15cm²= 22x 15cm²= 330cm²</h3>

<h3>are of shaded region</h3>

= area of whole rectangle -area of unshaded region= 450cm²-330cm²= 120cm²

therefore 120 is correct answer

6 0

3 years ago