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Zigmanuir [339]
3 years ago
15

Perimeter, Area And Volume

Mathematics
1 answer:
Maslowich3 years ago
6 0

\large\huge\green{\sf{Answer:-}}

<h3>area of shaded figure= </h3>

<h2>area of whole rectangle</h2>

= lengthx breadth=15x30= 450 cm²

<h3>area of unshaded region= lengthx breadth= (30-8)x 15cm²= 22x 15cm²= 330cm²</h3>

<h3>are of shaded region</h3>

= area of whole rectangle -area of unshaded region= 450cm²-330cm²= 120cm²

therefore 120 is correct answer

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Solve the logarithmic equation. Be sure to reject any value of x that is not in the domain of the original logarithmic expressio
KIM [24]

Answer:

Therefore x=9

Step-by-step explanation:

Give that,

log x+ log (x-3) = log 54

log x(x-3) =log 54             [    log_ca+log_c b=log_c(ab)   ]

x(x-3) = 54

Now expand the above equation to get a quadratic equation

x²-3x=54

⇒x²-9x+6x-54=0

⇒x(x-9)+6(x-9)=0

⇒(x-9)(x+6)=0

⇒x-9=0  or, x+6=0

⇒x=9,-6

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log(-6)+log(-6-9)=log 54.

Since log (-6) does not exist.

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8 0
3 years ago
Say the fraction in unit form. 1/10
Anni [7]

Answer:

One tenth

Step-by-step explanation:

You state the number on top as is.

Numerator:

1 - one

2- two

and so on.

over the denominator

which you state as an ordinal number

2 = halves

3 = thirds

4 = fourths

5 = fifths

etc.

so 1/10 would be one over tenths but you say  one tenth.

5 0
3 years ago
ASAP! GIVING BRAINLIEST! Please read the question THEN answer correctly! No guessing.
Vesnalui [34]

Answer:

A

Step-by-step explanation:

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5 0
3 years ago
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Slav-nsk [51]

Answer:

x° = ∠OBR = ∠ABC (base angles of a cyclic isosceles trapezoid)

Step-by-step explanation:

APRB form a cyclic trapezoid

∠APO  = x° (Base angle of an isosceles triangle)

∠OPR  = ∠ORP (Base angle of an isosceles triangle)

∠ORB = ∠OBR (Base angle of an isosceles triangle)

∠APO + ∠OPR + ∠OBR = 180° (Sum of opposite angles in a cyclic quadrilateral)

Similarly;

∠ORB + ∠ORP + x°  = 180°

Since ∠APO = x° ∠ORB = ∠OBR and ∠OPR  = ∠ORP we put

We also have;

∠OPR = ∠AOP = ∠BOR (Alternate interior angles of parallel lines)

Hence 2·x° + ∠AOP = 180° (Sum of angles in a triangle) = 2·∠OBR + ∠BOR

Therefore, 2·x° = 2·∠OBR, x° = ∠OBR = ∠ABC.

6 0
3 years ago
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Aleonysh [2.5K]
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3 years ago
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