Is (8,8) a solution to the inequality y < 6x + 5?
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Answer:
Step-by-step explanation:
<u>Roots of a polynomial</u>
If we know the roots of a polynomial, say x1,x2,x3,...,xn, we can construct the polynomial using the formula
Where a is an arbitrary constant.
We know three of the roots of the degree-5 polynomial are:
We can complete the two remaining roots by knowing the complex roots in a polynomial with real coefficients, always come paired with their conjugates. This means that the fourth and fifth roots are:
Let's build up the polynomial, assuming a=1:
Since:
Operating the last two factors:
Operating, we have the required polynomial: