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kari74 [83]
3 years ago
11

If 3x - 1 = 11, what is the value of x2 + x?

Mathematics
2 answers:
makkiz [27]3 years ago
8 0
3x-1=11

Add 1 to both sides
3x=12

Divide both sides by 3
x=4

Plug the known x value into the expression x^2+x
4^2+4

Simplify
16+4
20

Final answer: 20
lianna [129]3 years ago
4 0
Okay. 3x - 1 is 11. Add 1 to both sides and you'll get 3x = 12. Divide both sides by 3, and you'll get x = 4. In this case, the problem will be written out as 4 * 2 + 4. Do order of operations. For this problem, we multiply first. 4 * 2 is 8. Next, we add. 8 + 4 = 12. The value of x2 + x is 12.
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Solve for U <br><br> 11=8+u/7.68
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\begin{gathered}\\ \sf\longmapsto 11=\frac{8+u}{7.68}\end{gathered}

\begin{gathered}\\ \sf\longmapsto 11 =  \frac{8 + u}{ \frac{192}{25} } \end{gathered}

\begin{gathered}\\ \sf\longmapsto 11=\frac{(8+u)×25}{192}\end{gathered}

\begin{gathered}\\ \sf\longmapsto 11=\frac{200+25u}{192}\end{gathered}

\begin{gathered}\\ \sf\longmapsto 2112=200+25u\end{gathered}

\begin{gathered}\\ \sf\longmapsto 2112-25u=200\end{gathered}

\begin{gathered}\\ \sf\longmapsto -25u=200-2112\end{gathered}

\begin{gathered}\\ \sf\longmapsto -25u=-1912\end{gathered}

\begin{gathered}\\ \sf\longmapsto u=\frac{1912}{25}\end{gathered}

<u>Alternate form:</u>

<u>u</u><u>=</u><u>76.48</u>

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