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Tcecarenko [31]
3 years ago
10

A square with diagonals is shown. The distance from one point to the middle point is 3. The length from the center point to anot

her point is 3.
What is the approximate side length of the square?

3.0 units
3.5 units
4.2 units
4.9 units
Mathematics
2 answers:
il63 [147K]3 years ago
7 0

Answer:

e2 is the point to me which you it see the world of

Step-by-step explanation:

no problem at least all and that need are can

Andre45 [30]3 years ago
5 0

Answer:

answer

4.2 units

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A dolphin swims 665,280 feet in 3 hours. Use the formula d = rt, where d represents distance, r represents rate, and t represent
liraira [26]

Answer:

Answers Below

Step-by-step explanation:

Part A:

r=d/t

Part B:

r=665280/3

r=221760

Part C:

221760/5280 = 42mph

Part D: Miles per Hour, because it is easier to understand

6 0
3 years ago
How to do this question by proving the identity?
jeyben [28]

\sin^3 \theta-\cos^3 \theta=(\sin \theta-\cos \theta)(\sin \theta\cos \theta+1)\\\\
(\sin \theta-\cos \theta)(\sin^2 \theta+\sin \theta\cos \theta +\cos^2 \theta)=(\sin \theta-\cos \theta)(\sin \theta\cos \theta+1)\\\\
(\sin \theta-\cos \theta)(\sin \theta\cos \theta+1)=(\sin \theta-\cos \theta)(\sin \theta\cos \theta+1)\\\\

6 0
4 years ago
the measure of one side of a square is (s+3) inches long. which pair of expressions both represent the perimeter of this square?
stich3 [128]
Answer:
perimeter = 4s + 12 inches
perimeter = 4(s+3) inches

Explanation:
We are given that the side length of the square is s+3 inches
In a square, all sides are equal. This means that all four sides are s+3 inches
Now, to get the perimeter, we would add all four sides as follows:
perimeter = s+3+s+3+s+3+s+3 = 4s + 12 inches
For a square, since all sides are equal, we can simply get the perimeter by multiplying the side length by 4 as follows:
perimeter = 4(s+3) inches

Hope this helps :)

4 0
3 years ago
Science
kherson [118]
<span>potential; kinetic is the answer.</span>
3 0
3 years ago
Read 2 more answers
CALC BC HELPPP!!!??? 100PTS!!!
lyudmila [28]

the assumption being that "x" is a plain variable whilst "y" is a function, that matters because the chain rule would be needed for a function, not so for a plain variable.

4x^2+4x+xy=5\implies 8x+4+\stackrel{\textit{product rule}}{\left( 1\cdot y+x\cdot \cfrac{dy}{dx} \right)}=0 \\\\\\ x\cfrac{dy}{dx}=-8x-4-y\implies \cfrac{dy}{dx}=\cfrac{-8x-4-y}{x}

now, we know that y(5) = -23, which is another way of saying that when x = 5, y = -23, but we already knew that, we can get that by simply plugging it into the equation hmmm y'(5), well

\left. \cfrac{dy}{dx}=\cfrac{-8x-4-y}{x} \right|_{\stackrel{x=5~}{\textit{\tiny y=-23}}}\implies \cfrac{-8(5)-4-(-23)}{5}\implies \cfrac{-21}{5}

8 0
3 years ago
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