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joja [24]
3 years ago
9

Find the least common multiple of 10,15,25 please no links or photo​

Mathematics
1 answer:
sergey [27]3 years ago
6 0

Answer:

150

Step-by-step explanation:

The LCM of 10,15,25 10 , 15 , 25 is 2⋅3⋅5⋅5=150 2 ⋅ 3 ⋅ 5 ⋅ 5 = 150 .

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7

Step-by-step explanation:

3 * 7 = 21

21 - 7 = 14

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  is proportional

Step-by-step explanation:

The ratio between words and minutes is a constant, so the relationship is proportional.

  45/1 = 90/2 = 135/3

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2.) You are buying gifts for 10 people. You decide to buy each person either a CD or a
Katena32 [7]

Answer:

a. The number of DVDs is 10 - c

b. The cost of the CDs is 12c

c. The cost of the DVDs is 20(10 - c)

d. The total cost of all gifts is 200 - 8c

Step-by-step explanation:

* <em>Lets explain how to solve the problem</em>

- You are buying gifts for 10 people

# You will buy 10 gifts

- The gifts are CD or DVD

# The total numbers of CDs and DVDs is 10

- The cost of each CD is $12 and the cost of each DVD is $20

a.

# c is the number of CDs

∵ You buy c CDs

∵ The total numbers of CDs and DVDs is 10 as we said up

∴ c + the numbers of DVDs = 10

- Subtract c from both sides

∴ The number of DVDs = 10 - c

* The number of DVDs is 10 - c

b.

∵ The number if CDs is c

∵ The cost of each CD is $12

∴ The cost of the CDs = 12 × c = 12c

* The cost of the CDs is 12c

c.

∵ The number of DVDs is 10 - c

∵ The cost of each DVD is $20

∴ The cost of the DVDs = 20(10 - c)

* The cost of the DVDs is 20(10 - c)

d.

∵ The cost of the CDs is 12c

∵ The cost of the DVDs is 20(10 - c)

- The total cost of all the gifts is the sum of the costs of CDs and DVDs

∴ The total cost of all gifts = 12c + 20(10 - c)

- Multiply the bracket by 20

∵ 20(10 - c) = 100(2) - 20(c) = 200 - 20c

∴ The total cost of all gifts = 12c + 200 - 20c

- Add like terms

∴ The total cost of all gifts = 200 - 8c

* The total cost of all gifts is 200 - 8c

3 0
3 years ago
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