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german
4 years ago
9

Can someone please help me explain what forces are acting when an apple is falling from a tree and rolling downhill. Use a simil

ar explanation to what forces act one you when you slip over on a wet soapy floor. images are provided.
Pls answer ASAP.
Thanks​

Physics
1 answer:
katovenus [111]4 years ago
8 0

<h2>The forces acting on the body</h2>

Explanation:

When an apple falls from tree , The forces acting are

( i ) Gravitation force acts downwards due to pull of the earth .

( ii ) The force of friction due to air acts upwards

When it rolls down the hill

( i )  The gravitational force due to earth acting downwards

( ii ) The force if friction due to surfaces in contact , acting upwards along the slope of the hill

When we slip on the floor

( i ) The horizontal forward force due to horizontal component of force of reaction by the floor .

( ii ) The frictional force acting in a backward direction , due to surfaces in contact .

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At an air show, a stunt pilot performs a vertical loop-the-loop in a circle of radius 3.63 x 103 m. During this performance the
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Answer:

189 m/s

Explanation:

The pilot will experience weightlessness when the centrifugal force, F equals his weight, W.

So, F = W

mv²/r = mg

v² = gr

v = √gr where  v = velocity, g = acceleration due to gravity = 9.8 m/s² and r = radius of loop = 3.63 × 10³ m

So, v = √gr

v = √(9.8 m/s² × 3.63 × 10³ m)

v = √(35.574 × 10³ m²/s²)

v = √(3.5574 × 10⁴ m²/s²)

v = 1.89 × 10² m/s

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3 years ago
What happens when you increase the number of slits per millimeter (decrease the spacing between slits)?
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Answer:

Increasing the number of slits not only makes the diffraction maximum sharper, but also much more intense. If a 1 mm diameter laser beam strikes a 600 line/mm grating, then it covers 600 slits and the resulting line intensity is 90,000 x that of a double slit. Such a multiple-slit is called a diffraction grating.

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3 years ago
The gravitational potential is a distance z=0.17 m away from a distribution of mass that has the following equation:
sveta [45]

gravitational potential is given as

V = \frac{GM}{R^2}(R^2 + Z^2)^0.5

E = -\frac{dV}{dz}

E = -\frac{GM}{R^2}\frac{d}{dz}(R^2+z^2)^0.5

E  = -\frac{GM}{R^2}*0.5(R^2+z^2)^-0.5*2z

E = -\frac{GM*z}{R^2*(R^2 + z^2)^0.5}

now plug in all values given

M = 110 kg

R = 0.55 m

z = 0.17 m

E = -\frac{6.67 * 10^{-11}* 110*0.17}{0.55^2*(0.55^2 + 0.17^2)^0.5}

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3 years ago
Angle of reflection <br>​
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The angle of reflection equals the angle of Incidence

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The Law Of Reflection

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3 years ago
The average threshold of dark-adapted (scotopic) vision is 4.00 10-11 W/m2 at a central wavelength of 500 nm. If light with this
Studentka2010 [4]

Answer:

E = h f = h c / λ     energy of single photon

n E = 4.00E-11 W/m^2       energy required for visibility

n h c / λ = 4.00E-11          number of photons required for visibility (per square meter)

n = 4.00E-11 * 5.00E-7 / (6.63E-34 * 3.00E8)

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