Answer:
the maximum intensity of an electromagnetic wave at the given frequency is 45 kW/m²
Explanation:
Given the data in the question;
To determine the maximum intensity of an electromagnetic wave, we use the formula;
= 
ε₀cE
²
where ε₀ is permittivity of free space ( 8.85 × 10⁻¹² C²/N.m² )
c is the speed of light ( 3 × 10⁸ m/s )
E is the maximum magnitude of the electric field
first we calculate the maximum magnitude of the electric field ( E )
E = 350/f kV/m
given that frequency of 60 Hz, we substitute
E = 350/60 kV/m
E = 5.83333 kV/m
E = 5.83333 kV/m × ( 
)
E = 5833.33 N/C
so we substitute all our values into the formula for intensity of an electromagnetic wave;
= ε₀cE²
= × ( 8.85 × 10⁻¹² C²/N.m² ) × ( 3 × 10⁸ m/s ) × ( 5833.33 N/C )²
= 45 × 10³ W/m²
= 45 × 10³ W/m² × ( 
)
= 45 kW/m²
Therefore, the maximum intensity of an electromagnetic wave at the given frequency is 45 kW/m²
Answer:
Most metals are in the liquid state at room temperature.<u>False</u><u>.</u>
Explanation:
it needs excess heat except mercury and lithium.
Answer:
False
Explanation:
The direction of magnetic field on a current carrying conductor can be determined by the Fleming's right hand rule where
- The thumb represents the direction of motion
- the index finger represents the direction of field.
- The middle finger is the direction of induced current.
When two conductors carrying currents flowing in opposite direction, the magnetic field will be in the same direction hence they will repel.
<u><em>When the currents in them flow in same direction, then it means the magnetic field will be opposition and there will be a force of attraction between the conductors.</em></u>
Answer:
C. Heavy
Explanation:
You need to be able to lift the bat.
Explanation:
Below is an attachment containing the solution.
