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Free_Kalibri [48]
4 years ago
5

Multiply the polynomials (2x^2+6x+6)(3x-2)

Mathematics
2 answers:
Gala2k [10]4 years ago
8 0
That’s the answer tried my best because my sister had that problem

sdas [7]4 years ago
6 0

Answer:

6x^3 + 14x^2 + 6x - 12

Step-by-step explanation:

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-2x + y=5 and -5x + y = -4 cooridbnates of the solution to this system of equation
Viktor [21]

Answer:

(3,11)

Step-by-step explanation:

Turn both equations into linear equations:

y=2x+5

y=5x-4

Then, just graph both equations.

Find the point where the two lines intersect. That point of intersection is  the solution. That coordinate is (3,11).

8 0
3 years ago
Find the unknown side of a rectangle solid. V=30 cm3, H=3 cm, W=5 cm
Alex17521 [72]
V = 30cm³
H = 3cm
W = 5cm
L = ?

V = H × W × L

therefore:
3 × 5 × L = 30
15L = 30
L = 30 : 15
<u>L = 2 (cm)</u>
8 0
3 years ago
There are 124 students making 3 stars each for the
forsale [732]

Answer:

D

Step-by-step explanation

124 times 3 is 372

8 0
3 years ago
Read 2 more answers
A veterinarian estimated the weight of a puppy to be 7 kg. The actual weight of the puppy was 6.6 kg.
KIM [24]

9514 1404 393

Answer:

  • absolute error: 0.4 kg
  • relative error: 6.1%

Step-by-step explanation:

The absolute error is the difference between the estimate and the actual weight:

  7.0 kg -6.6 kg = 0.4 kg . . . . absolute error

__

The relative error is the ratio of the absolute error to the actual weight:

  (0.4 kg)/(6.6 kg) × 100% = 6.060606...% ≈ 6.1% . . . . relative error

6 0
3 years ago
A card is drawn at random from a standard deck of playing cards (no jokers). If the card is a spade, the player wins $7; if it i
Akimi4 [234]

The expected value of the game is the mean value of the game

The expected value of the game is $1

<h3>How to determine the expected value?</h3>

There are 13 spades in a deck of card of 52

So, the probability of selecting a spade is:

P(Spade) = 13/52

Simplify

P(Spade) = 1/4

Winning = $7

The probability of not selecting a spade is:

P(Not spade) = 1 - 1/4

Simplify

P(Not spade) = 3/4

Lose = $1

The expected value of the game is:

E(x) = \sum x * P(x)

This gives

E(x) = \frac 14 * 7 - 1 * \frac34

Simplify

E(x) = \frac 74 - \frac34

Evaluate

E(x) = 1

Hence, the expected value of the game is $1

Read more about expected values at:

brainly.com/question/15858152

8 0
3 years ago
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