3 years ago

Please help ASAP! thank you

Mathematics

1 answer:

AysviL [449]3 years ago

6 0

Answer:

Step-by-step explanation:

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Step-by-step explanation:

Q is not inversible if det(Q)=0

$\left|\begin{array}{ccc}6&7&-1\\3&n&5\\9&11&n\end{array}\right| =0\\\\\\\\6(n^2-55)-3(7n+11)+9(35+n)=0\\\\n^2-2n-8=0\\\\\Delta=36=6^2\\\\n=\dfrac{2-6}{2} =-2\ or\ n=\dfrac{2+6}{2}=4\\$