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3 years ago

Help me with this please

Mathematics

1 answer:

Damm [24]3 years ago

6 0

Answer:

200

Step-by-step explanation:

Brainiest please it is 100% correct

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Indicate the data relationship for each table. If each is, directly proportional or non-proportional

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It’s nonporportiniol sorry if it’s spelled wrong lol

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3 years ago

Four times a number<br> decreased by ten is 34.<br> Write an equation & solve.

igomit [66]

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4 years ago

One pound of nuts costs $2.80. Aaron bought 2 pounds of nuts. He gave the clerk a $10.00 bill. How much change did he get?

MA_775_DIABLO [31]

The answer would be D.
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4 0

2 years ago

Read 2 more answers

A standard weight known to weigh 10 grams. Some suspect bias in weights due to manufacturing process. To assess the accuracy of

notsponge [240]

Answer:

a) The 98% confidence interval for the mean weight is between 10.00409 grams and 10.00471 grams

b) 49 measurements are needed.

Step-by-step explanation:

Question a:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.98}{2} = 0.01$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.01 = 0.99$ , so Z = 2.327.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 2.327\frac{0.0003}{\sqrt{5}} = 0.00031$

The lower end of the interval is the sample mean subtracted by M. So it is 10.0044 - 0.00031 = 10.00409 grams

The upper end of the interval is the sample mean added to M. So it is 10 + 0.00031 = 10.00471 grams

The 98% confidence interval for the mean weight is between 10.00409 grams and 10.00471 grams.

(b) How many measurements must be averaged to get a margin of error of +/- 0.0001 with 98% confidence?

We have to find n for which M = 0.0001. So

$M = z\frac{\sigma}{\sqrt{n}}$

$0.0001 = 2.327\frac{0.0003}{\sqrt{n}}$

$0.0001\sqrt{n} = 2.327*0.0003$

$\sqrt{n} = \frac{2.327*0.0003}{0.0001}$

$(\sqrt{n})^2 = (\frac{2.327*0.0003}{0.0001})^2$

$n = 48.73$

Rounding up

49 measurements are needed.

7 0

3 years ago

Okay last one. Someone help me please??

olga55 [171]

Answer:

The missing side (c) is 87 ft.

Step-by-step explanation:

5 0

3 years ago