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2 years ago

Make x the subject of the formula (mx^2=f)

Mathematics

1 answer:

wolverine [178]2 years ago

4 0

Answer:

x = ± $\sqrt{\frac{f}{m} }$

Step-by-step explanation:

Given

mx² = f ( isolate x² by dividing both sides by m )

x² = $\frac{f}{m}$ ( take the square root of both sides )

x = ± $\sqrt{\frac{f}{m} }$

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A company's mean salary is $65,000 with a standard deviation of $6,000. If a sample of

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Step-by-step explanation:

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2 years ago

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Paying $38.50 for 12 pounds of apples

ch4aika [34]

Each pound of apples is $3.21

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2 years ago

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Amelia inserted parentheses to the numerical expression 12 ÷ 2 + 4 × 3 + 5 so that the value of her expression was 16. Which of

denis-greek [22]

Answer:

D. 12 ÷ (2 + 4) × (3 + 5)

Step-by-step explanation:

12 ÷ (2 + 4) × (3 + 5)

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3 0

2 years ago

A waitress sold 15 ribeye steak dinners and 14 grilled salmon dinners, totaling $583.59583.59 on a particular day. another day

Ratling [72]

Answer:

Step-by-step explanation:

This is a systems of equations question. Let's set ribeye steak to the variable r, and grilled salmon to s.

We get these two equations:

13r + 18s = 550.25

22r + 6s = 582.08

First, we'll isolate one variable in the first equation. Let's choose r:

13r = 550.25 - 18s

r = 42.33 - 1.38s

Now, we'll take this value for r and plug it into the second equation:

22r + 6s = 582.08

22 (42.33 - 1.38s) + 6s = 582.08

(931.19 - 30.46s) + 6s = 582.08 | multiply values by 22

931.19 - 24.46s = 582.08 | combine s values

349.11 = 24.46s | move 582.08 to left side, and combine; move -24.46s to right side

14.27 = s | solve for s

Now, plug this value for s back into the first equation:

13r + 18s = 550.25

13r + 18 (14.27) = 550.25

13r = 256.91 = 550.25

13r = 293.34

r = 22.56

So r = 22.56 and s = 14.27.

The ribeye steak dinners cost $22.56 each and the grilled salmon dinners cost $14.27 each.

Note, this solution does not factor in any tips the waitress makes on each dinner!

7 0

2 years ago

A dealer bought an article for Rs1500 and sold it at 20 percent profit . what was rhe sale price of the article?

umka2103 [35]

$\large\underline{\underline{\red{\rm\blue{\longmapsto} Step-by-step\: Explanation:-}}}$

Given that , a dealer bought an article for Rs 1500 and sold it at a profit of 20% .

So , here ,

Cost price of the article = Rs 1500.
Profit on the article = 20% .

Since the article is sold at profit , the Selling price of the article will equal to Cost price + 20% of cost price .

Firstly let's Calculate 20% of 1500 .

= 20% of Rs 1500 .

= 20/100 × Rs 1500 .

= Rs 300 .

Hence we can find now Selling price as ,

$\boxed{\green{\bf Selling\: Price=Cost\:Price+Profit}}$

⇒ SP = CP + Profit .

⇒ SP = Rs ( 1500 + 300 ).

⇒ SP = Rs 1800 .

Hence the required answer is Rs 1800.

5 0

2 years ago