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3 years ago

All of the following are possible sources of error in a scientific investigation except for

Physics

2 answers:

nikdorinn [45]3 years ago

5 0

Answer:

The answer is A). Having a control group is usually a very beneficial thing for an experiment. Hope this helps! :)

AnnZ [28]3 years ago

5 0

Answer:

The correct answer will be option-having a constant in your experiment.

Explanation:

A scientific investigation is a systematic approach to understand and explain the natural phenomenon that takes place in nature.

The recording of accurate data plays an important role in the scientific investigation as the results prove or disprove the predicted hypothesis through experiment.

The error in collection of data can cause the error in drawing the conclusions from the results and the most possible sources of error in data could be the incorrect and wrong way of measurement and having no replicas or trials of the sample.

The constant variable does not influence the conclusion as it is kept constant and thus is the correct answer.

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A grating has 460 rulings/mm. What is the longest wavelength for which there is a 6.0th-order diffraction line

mestny [16]

Answer:

λ = 3.62 x 10⁻⁷ m = 362 nm

Explanation:

The grating equation gives the relationship between the wavelength, the diffraction line order and the diffraction angle. The grating equation is written as follows:

mλ = d Sinθ

where,

m = order of diffraction = 6

λ = longest wavelength = ?

d = 1/(460 rulings/mm)(1000 mm /1 m) = 2.17 x 10⁻⁶ m/ruling

θ = Diffraction angle = 90° (for longest wavelength)

(6)λ = (2.17 x 10⁻⁶ m/ruling) Sin 90°

λ = (2.17 x 10⁻⁶ m/rulings)/6

λ = 3.62 x 10⁻⁷ m = 362 nm

3 0

4 years ago

Define the following:

belka [17]

Define the following:
Potential energy: In physics, potential energy is the energy held by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors.
Kinetic energy: In physics, the kinetic energy of an object is the energy that it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes.
Mechanical energy:
Chemical energy: chemical energy, Energy stored in the bonds of chemical compounds. Chemical energy may be released during a chemical reaction, often in the form of heat; such reactions are called exothermic. Reactions that require an input of heat to proceed may store some of that energy as chemical energy in newly formed bonds
Sound energy: In physics, sound energy is a form of energy that can be heard by living things. Only those waves that have a frequency of 16 Hz to 20 kHz are audible to humans. However, this range is an average and will slightly change from individual to individual.
Light energy: Light energy is a kind of kinetic energy with the ability to make types of light visible to human eyes. Light is defined as a form of electromagnetic radiation emitted by hot objects like lasers, bulbs, and the sun. Light contains photons which are minute packets of energy.
Nuclear energy: Nuclear power is the use of nuclear reactions to produce electricity. Nuclear power can be obtained from nuclear fission, nuclear decay and nuclear fusion reactions. Presently, the vast majority of electricity from nuclear power is produced by nuclear fission of uranium and plutonium in nuclear power plants

5 0

3 years ago

Read 2 more answers

A projectile of mass 6.8 kg kg is shot horizontally with an initial speed of 14.5 m/s from a height of 26.7 m above a flat deser

sleet_krkn [62]

Answer:

Explanation:

Given

mass of projectile $m=6.8\ kg$

initial horizontal speed $u_x=14.5\ m/s$

height $h=26.7\ m$

Considering vertical motion

velocity gained by projectile during 26.7 m motion

$v^2-u^2=2 as$

v=final velocity

u=initial velocity

a=acceleration

s=displacement

$v^2-(0)^2=2\times (9.8)\times (26.7)$

$v=\sqrt{523.32}$

$v=22.87\ m/s$

Horizontal velocity will remain same as there is no acceleration

final velocity $v_{net}=\sqrt{(v)^2+(u_x)^2}$

$v_{net}=\sqrt{733.57}=27.08\ m/s$

Initial kinetic Energy $K_i=\frac{1}{2}mu_x^2$

$K_i=\frac{1}{2}\times 6.8\times (14.5)^2=714.85\ J$

Final Kinetic Energy $K_f=\frac{1}{2}mv_{net}^2$

$K_f=\frac{1}{2}\times 6.8\times (27.08)^2$

$K_f=2493.30\ J$

Work done by all the force is equal to change in kinetic Energy of object

Work done by gravity is $W_g$

$W_g=\Delta K$

$W_g=2493.30-714.85=1778.45\ J$

8 0

3 years ago

The scientists that was the first to organize the elements into a table was

Murrr4er [49]

The first scientist was Mendeleev

5 0

3 years ago

Please help!!!!!!!!!!!!!!!

jenyasd209 [6]

7.1. The graph displays velocity over time, so the distance covered by "him" is equal to the unsigned (positive) area under the curve. (In contrast, the signed area represents displacement.) Finding this area is just an exercise in basic geometry.

• From time 0 to 3 s, the distance is equal to the area of a triangle with height 15 m/s and length 3 s:

1/2 (15 m/s) (3 s) = 22.5 m

• From 3 to 5.5 s, the distance is the area of a rectangle with height 15 m/s and length 5.5 s - 3 s = 2.5 s:

(15 m/s) (2.5 s) = 37.5 m

• From 5.5 to 6.5 s, you have a trapezoid with "bases" 15 m/s and 5 m/s, and "height" 6.5 s - 5.5 s = 1 s:

1/2 (15 m/s + 5 m/s) (1 s) = 10 m

• From 6.5 to 8 s, you have a triangle with height 5 m/s and length 8 s - 6.5 s = 1.5 s:

1/2 (5 m/s) (1.5 s) = 3.75 m

• From 8 to 9 s, another triangle with height 13 m/s and length 9 s - 8 s = 1 s:

1/2 (13 m/s) (1 s) = 6.5 m

• From 9 to 13 s, a rectangle with height 13 m/s and length 13 s - 9 s = 4 s:

(13 m/s) (4 s) = 52 m

• From 13 to 16.5 s, a triangle with height 13 m/s and length 16.5 s - 13 s = 3.5 s:

1/2 (13 m/s) (3.5 s) = 22.75 m

Add up the distances to get the total:

22.5 m + 37.5 m + 10 m + 3.75 m + 6.5 m + 52 m + 22.75 m = 155 m

7.2. The velocity is non-zero for any given time interval, so "he" is never at rest. (True, his velocity is 0 at 8 s, but only instantaneously.)

7.3. Given the plot of velocity, the acceleration is negative wherever the slope of the tangent line to the curve is negative. This happens in the interval from 5.5 to 9 s.

7.4. Similarly, positive acceleration corresponds to a positively-sloped tangent line. This happens from 0 to 3 s, and again from 13 to 16.5 s.

7.5. Where the velocity curve is horizontal, the accleration is zero, so you can ignore those intervals.

• From 0 to 3 s, the acceleration is

(15 m/s - 0 m/s)/(3 s - 0 s) = 5 m/s²

• From 5.5 to 6.5 s, it is

(5 m/s - 15 m/s)/(6.5 s - 5.5 s) = -10 m/s²

• From 6.5 to 8 s, it is

(0 m/s - 5 m/s)/(8 s - 6.5 s) ≈ -3.3 m/s²

• From 8 to 9 s, it is

(-13 m/s - 0 m/s)/(9 s - 8 s) = -13 m/s²

• From 13 to 16.5 s, it is

(0 m/s - (-13 m/s))/(16.5 s - 13 s) ≈ 3.7 m/s²

The clear winner is the interval from 8 to 9 s, where the acceleration has a magnitude of 13 m/s².

8. The magnitude of the velocity of the ball decreases until it reaches zero at its maximum height, then increases as it falls back down. Acceleration is constant and pointing downward the entire time.

4 0

3 years ago