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Alinara [238K]
4 years ago
14

A rigid tank whose volume is unknown is divided into two parts by a partition. One side of the tank contains an ideal gas at 927

°C. The other side is evacuated and has a volume twice the size of the part containing the gas. The partition is now removed and the gas expands to fill the entire tank. Heat is now transferred to the gas until the pressure equals the initial pressure. Determine the final temperature of the gas.
Physics
1 answer:
Marianna [84]4 years ago
4 0

Answer:

The final temperature will be 3600 K.

Explanation:

Side 1

T=927°C

T=1200 K

Lets take volume of one side is V then the volume of other side will be 2V. The final volume of system will become 3 V.

The system is closed so the mass of system will remain constant .

We know that for ideal gas  P V = m R T

The final pressure is same as initial pressure so we can say that

\dfrac{T_i}{V_i}=\dfrac{T_f}{V_f}

\dfrac{1200}{V}=\dfrac{T_f}{2V+V}

T_f=3600\ K

So the final temperature will be 3600 K.

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3 years ago
It's nighttime, and you've dropped your goggles into a 3.1-mm-deep swimming pool. If you hold a laser pointer 1.2 mm above the e
arlik [135]

Answer:

the googles are 4.33mm from the edge

Explanation:

In this question, we are asked to calculate the distance of a set of googles from the edge of a pool.

We proceed as follows;

depth of pool , d = 3.1mm

Now, let i be the angle of incidence

i = arctan(1.8/1.2)

i = 56.31 degree

Using snell's law ,

n1 * sin(i) = n2 * sin(r)

1 * sin(56.3) = 1.33 * sin(r)

r = 38.72 degrees

Now,

distance of googles = 1.8+ d*tan(r)

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5 0
3 years ago
What is the smallest resistance you can make by combining them?
Luda [366]

Answer:

166.67 ohm

Explanation:

Complete statement of the question is :

You have a collection of six 1.0 kO resistors. What is the smallest resistance you can make by combining them?

When we connect resistors in parallel, the combination resistance is always smaller than the smallest resistance value we combine.

Parallel Combination of resistances is given as

\frac{1}{R_{p}} = \frac{1}{R_{1}} +\frac{1}{R_{2}} +\frac{1}{R_{3}} + ....

where

R_{p} = Equivalent resistance

and R_{1} , R_{2}, R_{3} are resistances in parallel.

So for the above question, we have

R_{1} = R_{2} = R_{3} = R_{4} = R_{5} = R_{6} = 1 kohm = 1000 ohm

So parallel combination is given as

\frac{1}{R_{p}} = \frac{1}{R_{1}} +\frac{1}{R_{2}} +\frac{1}{R_{3}} +\frac{1}{R_{4}} +\frac{1}{R_{5}} +\frac{1}{R_{6}}\\\frac{1}{R_{p}} = \frac{1}{1000} +\frac{1}{1000} +\frac{1}{1000} +\frac{1}{1000} +\frac{1}{1000} +\frac{1}{1000}\\R_{p} = \frac{1000}{6} \\R_{p} = 166.67 ohm

So the smallest resistance is 166.67 ohm

8 0
4 years ago
An animal-rescue plane flying due east at 55 m/s drops a bale of hay from an altitude of 69 m . The acceleration due to gravity
Bogdan [553]

Answer:

The momentum of the bale the moment it strikes the ground is 1076.68 kg-m/s.

Explanation:

It is given that,

Velocity of an animal-rescue plane, v_x=55\ m/s

It drops a bale of hay from an altitude of 69 m, h = 69 m

The vertical velocity of plane is given by :

v_y=\sqrt{2gh}

v_y=\sqrt{2\times 9.81\times 69} =36.79\ m/s

Weight of the bale of hay, W = 192 N

If m is the mass, then weight is given by :

m=\dfrac{W}{g}

m=\dfrac{192}{9.81}=19.57\ kg

The resultant momentum of the bale the moment it strikes the ground is given by :

p=m(v_x-v_y)

p=19.57\times 55i-19.57\times 36.79j

p=(1076.35i-719.98j)\ kg-m/s

Magnitude of momentum,

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p = 1076.68 kg-m/s

So, the momentum of the bale the moment it strikes the ground is 1076.68 kg-m/s. Hence, this is the required solution.

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