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3 years ago

13

Please help me with this !!! Thank you

1 answer:

puteri [66]3 years ago

8 0

Answer:

messages me i will explain how to solve if i can

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Adam works at a bakery. He uses 1/8 of his flour supply to make bread and 3/4 of his flour supply to make other baked goods. If

kykrilka [37]

Answer: B

he has 24 in his supply!

Step-by-step explanation:

7 0

3 years ago

A spinner numbered 1 through 12 is spun. Find the probability that

anastassius [24]

Answer:

$\dfrac{1}{6}$

Step-by-step explanation:

Let <em>A</em> be the event of getting an odd number.

<em>P(A)</em> be the probability of getting an odd number.

Total odd numbers here are 6 i.e. $\{1,3,5,7,9,11\}$

Here, total numbers in the game are 12 i.e $\{1,2,3,....,12\}$ .

Formula for probability of an <em>event E</em> can be observed as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

$P(A) = \dfrac{6}{12}\\\Rightarrow \dfrac{1}{2}$

Let <em>B</em> be the event of getting 11.

<em>P(B)</em> be the probability of getting 11.

Total number of possible cases is 1.

$P(B) = \dfrac{1}{12}$

$P(A \cap B)$ is the probability that we get 11 and an odd number.

Possible number of cases = 1

$P(A\cap B) = \dfrac{1}{12}$

<em>P(B/A)</em> is the probability that we get an 11 given that it is an odd number.

$P(B/A) = \dfrac{P(A \cap B)}{P(A)}\\\Rightarrow \dfrac{\dfrac{1}{12}}{\dfrac{1}{2}}\\\Rightarrow \dfrac{1}{6}$

Hence, P(B/A) = $\dfrac{1}{6}$

4 0

3 years ago

Read 2 more answers

Round <br> 0.655<br> to one decimal place.

Virty [35]

Answer:

0.7

Step-by-step explanation:

If we're rounding to one decimal place, we need to round up since it's 0.65.

8 0

3 years ago

Read 2 more answers

Can someone plz help with this asap

Lera25 [3.4K]

Answer:

Horizontal lines are parallel to the x-axis

The answer is the second option

6 0

3 years ago

Pleasee help ASAP!! No links pleaseee!!!

Ilya [14]

Given:

The vertices of the rectangle ABCD are A(0,1), B(2,4), C(6,0), D(4,-3).

To find:

The area of the rectangle.

Solution:

Distance formula:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using the distance formula, we get

$AB=\sqrt{(2-0)^2+(4-1)^2}$

$AB=\sqrt{(2)^2+(3)^2}$

$AB=\sqrt{4+9}$

$AB=\sqrt{13}$

Similarly,

$BC=\sqrt{(6-2)^2+(0-4)^2}$

$BC=\sqrt{(4)^2+(-4)^2}$

$BC=\sqrt{16+16}$

$BC=\sqrt{32}$

$BC=4\sqrt{2}$

Now, the length of the rectangle is $AB=\sqrt{13}$ and the width of the rectangle is $BC=4\sqrt{2}$ . So, the area of the rectangle is:

$A=length \times width$

$A=\sqrt{13}\times 4\sqrt{2}$

$A=4\sqrt{26}$

$A\approx 20$

Therefore, the area of the rectangle is 20 square units.

3 0

3 years ago