Please help me with this !!! Thank you

Please help me out don’t waste my question and explain your answer for I can believe you did just pick a random letter.

LiRa [457]

Answer:

A is the answer

5 0

2 years ago

Read 2 more answers

Thank you guys for helping me I know I'm being annoying

Ierofanga [76]

A² + b² = c²

c² = 4² + 6.5²

c² = 58.25

c = 7.63

Perimeter = 4 + 6.5 + 7.63 = 18.13 units.

Perimeter after the increase in scale = 18.13 x 4 = 72.52 units.

Answer: 72.52 units

8 0

2 years ago

Who plays forza horizon 3

Butoxors [25]

Answer:

I recently got it on my xbox

Step-by-step explanation:

I usually play with the family my name on xbox is wood

8 0

2 years ago

Read 2 more answers

A drug company is considering marketing a new local anesthetic. The effective time of the anesthetic the drug company is current

lapo4ka [179]

Using the z-distribution, we have that:

a)

The hypothesis test is:

$H_0: \mu = 7.4$

$H_1: \mu < 7.4$

The p-value is of 0.0668.

The critical value is $z^{\ast} = -1.28$

b) Since the test statistic is less than the critical value for the left-tailed test, there is enough evidence to conclude that the null hypothesis will be rejected.

Item a:

At the null hypothesis, it is tested if the mean is of 7.4 minutes, that is:

$H_0: \mu = 7.4$

At the alternative hypothesis, it is tested if the mean is lower than 7.4 minutes, that is:

$H_1: \mu < 7.4$

We have the standard deviation for the population, hence, the z-distribution is used.

The test statistic is given by:

$z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.

$\mu$ is the value tested at the null hypothesis.

$\sigma$ is the standard deviation of the sample.

n is the sample size.

For this problem, the values of the parameters are: $\overline{x} = 7.1, \mu = 7.4, \sigma = 1.2, n = 36$ .

Hence, the value of the test statistic is:

$z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{7.1 - 7.4}{\frac{1.2}{\sqrt{36}}}$

$z = -1.5$

Using a z-distribution calculator, the p-value is of 0.0668.

Also using a calculator, considering a left-tailed test, as we are testing if the mean is less than a value, the critical value with a significance level of 0.1 is of $z^{\ast} = -1.28$ .

Item b:

Since the test statistic is less than the critical value for the left-tailed test, there is enough evidence to conclude that the null hypothesis will be rejected.

You can learn more about the use of the z-distribution to test an hypothesis at brainly.com/question/16313918

5 0

2 years ago

A bank manager is interested in the average length of time that customers are willing to wait in line before they give up and le

Fynjy0 [20]

Answer: The average length of time that the 25 customers waited before leaving the bank. e. Statistic

The list of times for the 25 customers who left the bank. f.Data

All of the bank's customers d. Population

The 25 customers that the manager observed leave. c. Sample

The length of time a customer waits before leaving the bank. a. Variable.

The average length of time that all customers will wait before leaving the bank a. Parameter

Step-by-step explanation:

A data is a list of observations.

In statistics, a variable is an attribute that defines a person, place, thing, or thought.

A large group that have similar individuals as per the researcher's point of view is known as population, where its subset is known as sample.

The measure of certain characteristic in population is known as parameter, where for sample it is known as statistic.

8 0

3 years ago