The answer would be y=42x
we know XYZ is an isosceles, thus XY = YZ, the perpendicular segment bisectors of QR and QS are also equal to each other in length, because they both are segment bisectors and thus YR=RX=YS=SZ, so any perpendicular line stemming from the same length on each side will meet its counterpart right on the middle of the triangle.
![\bf \stackrel{QR}{\cfrac{x}{2}+2}~~=~~\stackrel{QS}{x - 10}\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{2}}{2\left( \cfrac{x}{2}+2 \right)=2(x-10)}\implies x+4=2x-20 \\\\\\ 4=x-20\implies 24=x \\\\[-0.35em] ~\dotfill\\\\ \stackrel{QR}{\cfrac{24}{2}+2}\implies 12+2\implies 14](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7BQR%7D%7B%5Ccfrac%7Bx%7D%7B2%7D%2B2%7D~~%3D~~%5Cstackrel%7BQS%7D%7Bx%20-%2010%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bmultiplying%20both%20sides%20by%20%7D%5Cstackrel%7BLCD%7D%7B2%7D%7D%7B2%5Cleft%28%20%5Ccfrac%7Bx%7D%7B2%7D%2B2%20%5Cright%29%3D2%28x-10%29%7D%5Cimplies%20x%2B4%3D2x-20%20%5C%5C%5C%5C%5C%5C%204%3Dx-20%5Cimplies%2024%3Dx%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7BQR%7D%7B%5Ccfrac%7B24%7D%7B2%7D%2B2%7D%5Cimplies%2012%2B2%5Cimplies%2014)
Answer:
2x2+ 4 The area is 4 in
Step-by-step explanation:
K, remember
(ab)/(cd)=(a/c)(b/d) or whatever
also

and

and
![x^ \frac{m}{n}= \sqrt[n]{x^m}](https://tex.z-dn.net/?f=x%5E%20%5Cfrac%7Bm%7D%7Bn%7D%3D%20%5Csqrt%5Bn%5D%7Bx%5Em%7D%20%20)
and

and

and
(a/b)/(c/d)=(a/b)(d/c)=(ad)/(bc)
so

=

=

=

=


=

=
6*45=270 is the first step you should do to get the answer you are looking for. The next thing I would do is go to all the answers to see which one comes out the same way. The first one comes to be 246, the next one is 54, the next is 270 and the last one is 220. 6*40+6*5 is the correct answer.