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antoniya [11.8K]
3 years ago
10

I NEED HELP PLEASE PLEASE HELP ME !!!! :(

Mathematics
1 answer:
stepan [7]3 years ago
7 0

Answer:

( 3 , 25.5 )

Step-by-step explanation:

1. Plug in the equation of y into the first equation

2. Solve for x by merging together like terms from both sides

3. plug in x into the y equation

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If you drive 27.54 km to school and then 21.86 km to your<br> friends, how far do you drive?
AlekseyPX

Answer:

49.4 km

Step-by-step explanation:

you add 27.54 plus 21.86 so 49.4 km total between school and to your friends house

4 0
3 years ago
Sandra wants to buy a new mp3 player that is on sale for $95 she has saved $73 how much more money does she need
Schach [20]

Answer:

For Sandra to save up and purchase the mp3 she must save additional $22.

Step-by-step explanation:

This problem requires us to understand the concerns of deficit/balance

Step one

We were told that mp3 cost $95

And Sandra has saved $73

Hence for her to purchase the mp3 she has to save up to $95 which is the benchmark price for the item

Step two :

Hence the amount of money to balance up is

=Cost of mp3- Sandra's savings

= $95-$73

=$22

5 0
3 years ago
Read 2 more answers
Select all expressions that are equivalent to 2+y+y+y+y+y+3?
ryzh [129]
I can’t see your choices, but this equation can be simplified to 5y + 5.

If you add the choices as a comment, I’m happy to help more.
7 0
3 years ago
What equation is graphed in this figure? A- y−4=−23(x+2) B-y+2=−32(x−2) C-y−3=32(x+1) D- y+1=−23(x−3)
UkoKoshka [18]
B, -y+w=-32(x-2) is the correct answer
8 0
3 years ago
Read 2 more answers
Solve the system using either Gaussian elimination with back-substitution or Gauss-Jordan elimination. (If there is no solution,
Gnom [1K]

Answer:

x1=-4/5, x2=18/5 and x3=7/5

Step-by-step explanation:

\left[\begin{array}{ccc|c}1&0&-3&-5\\3&1&2&4\\2&2&1&7\end{array}\right]

you can do linear combination between the rows:

2nd row=R2-3R1 and 3th row=R3-2R1

\left[\begin{array}{ccc|c}1&0&-3&-5\\0&1&11&19\\0&2&7&17\end{array}\right]

3th row=(3R2-R3)/15

\left[\begin{array}{ccc|c}1&0&-3&-5\\0&1&11&19\\0&0&1&\frac{7}{5} \end{array}\right]

1st row=R1+3R3 and R2-11R3

\left[\begin{array}{ccc|c}1&0&0&-4/5 \\0&1&0&18/5 \\0&0&1&7/5\end{array}\right]

x1=-4/5, x2=18/5 and x3=7/5

6 0
3 years ago
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