Step-by-step explanation:
x=14-6y/3
substituting x=14-6y/3 into eqn 2
2(14-6y/3)+8y=2
multiplying through by 3
2(14-6y/3)×3 +8y×3=2×3
2(14-6y)+24y=6
28-12y+24y=6
28-12y=6
28-6=12y
22=12y
22/12=y
finding x
2x+8(22/12)=2
2x+44/3=2
2x=2-44/3
x=(-38/3)/2
×=-38/6
1.403 > 1.1
1.1 = 1.100
1.403>1.100
C. 4 because 4 is a perfect square, as well as x^2 and 4x
I hope that helps!
Answer:
- solutions: (2, 10), (4, 5)
- non-solutions: all other points
Step-by-step explanation:
It can be useful to graph the inequalities related to Tyler's limits of money and weight.
1x +3y ≤ 36 . . . . . . the limit on the cost of the items Tyler can afford
1x +1.5y ≤ 20 . . . . . the limit on the weight of the items Tyler can carry
Then plotting the given points shows that only (2, 10) and (4, 5) are in the doubly-shaded area that is the solution space. The other points are not a solution.
Answer:
36
Step-by-step explanation:
Here we a given a rule
It say
÷
And we are given the values of x and y as
x=4 and y = 9
Let us replace them in the rule we are provided with
÷
Applying DMAS rule, which says, first Division ollowed by Multiplication addition and then subtraction .
We first divide 9 by 3
9÷3 = 3
Hence
÷
Now we square first



Hence our final answer will be 36