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3 years ago

I'll give brainliest and five stars if you help me!

Mathematics

1 answer:

andrezito [222]3 years ago

6 0

A.)))))))))))

- Harvard university professor

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If 2m + 2p = 16, p equals

adelina 88 [10]

2m + 2p = 16 Subtract 2m from both sides
2p = 16 - 2m Divide both sides by 2
p = 8 - m

8 0

3 years ago

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Very large or very small numbers are best input with exponential notation. For instance, the number 8,000,000 (eight million) is

Lerok [7]

Answer:

$9*10^{12}km$

Step-by-step explanation:

$9,460,730,472,580.8 km$

First, we can work out 5% of our number, by multiplying it by 0.05

$9,460,730,472,580.8 * 0.05 = 473,036,523,629$

Now, if we add and subtract our 5% calculated from our original number, we can work out the minimum and maximum value that our final answer can be in the range of.

$9,460,730,472,580.8 + 473,036,523,629 = 9.933767*10^{12}\\9,460,730,472,580.8 - 473,036,523,629 =8.98769395*10^{12}$

We can see that $9*10^{12}$ is in the range of valid answers, as:

$8.9*10^{12} \leq 9*10^{12} \leq 9.9 * 10^{12}$

So, our final answer is:

$9*10^{12}km$

5 0

3 years ago

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Isabella works at Baker's Book company. If she earned a commission of $63.75 on her sales of $850, what was Isabella's rate of c

Westkost [7]

Rate = 63.75/850=.075*100%= 7.5%

7.5% is Isabella's rate of commission.

8 0

3 years ago

4. In a sample of 1000 people, 130 can wiggle their ears. Two unrelated people are

Elina [12.6K]

Using the hypergeometric distribution, it is found that there is a 0.7568 = 75.68% probability that neither can wiggle his or her ears.

The people are chosen from the sample without replacement, which is why the <u>hypergeometric distribution</u> is used to solve this question.

Hypergeometric distribution:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.
N is the size of the population.
n is the size of the sample.
k is the total number of desired outcomes.

In this problem:

1000 people means that $N = 1000$
130 can wiggle their ears, thus $k = 130$
Two are selected, thus $n = 2$ .

The probability that neither can wiggle his or her ears is P(X = 0), thus:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}$

$P(X = x) = h(0,1000,2,130) = \frac{C_{130,0}C_{870,2}}{C_{1000,2}} = 0.7568$

0.7568 = 75.68% probability that neither can wiggle his or her ears.

A similar problem is given at brainly.com/question/24826394

5 0

3 years ago

PLEASE HELP ME WITH THANKS :)

Maurinko [17]

Answer

12855.04 ft³

Step-by-step explanation:

regular Octagon consists of 8 congruent triangles

B = (13.28 x 11) / 2 x 8=584.32

V = BH = 584.32 x 22 = 12855.04

8 0

3 years ago

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