Answer:
Orion's belt width is 184 light years
Step-by-step explanation:
So we want to find the distance between Alnitak and Mintaka, which is the Orions belts
Let the distance between the Alnitak and Mintaka be x,
Then applying cosine
c²=a²+b²—2•a•b•Cosθ
The triangle is formed by the 736 light-years and 915 light years
Artemis from Alnitak is
a = 736lightyear
Artemis from Mintaka is
b = 915 light year
The angle between Alnitak and Mintaka is θ=3°
Then,
Applying the cosine rule
c²=a²+b²—2•a•b•Cosθ
c² =736² + 915² - 2×, 736×915×Cos3
c² = 541,696 + 837,225 - 1,345,034.1477702404
c² = 33,886.85222975954
c = √33,886.85222975954
c = 184.0838184897 light years
c = 184.08 light years
So, to the nearest light year, Orion's belt width is 184 light years
Expanding the given expressions using Foil:
1)(–7x + 4)(–7x + 4) =
2) (–7x + 4)(4 – 7x)=
3)(–7x + 4)(–7x – 4)=
=
4)(–7x + 4)(7x – 4)=
The third option that is (–7x + 4)(–7x – 4) is difference of two squares.
Answer:
(36^t) / (6^(t^2)) is nonequivalent
(6^(t^2)) / (36^t) is equivalent
(6^(t^2)) * 36^t is nonequivalent
Step-by-step explanation:
We can use the exponential quotient law for this problem.
a^x / a^y = a^x - y
(6^(t^2)) / (6^2t) = (6^(t^2)) / (36^t)
Hello :
<span>f(x)=x²+4x-5
</span><span>The axis of symmetry for a function in the form f(x)=x^2+4x-5 is x=-2 :
</span>f(x) = (x+2)² + b
f(x) x²+4x+4+b= x² +4x-5
4+b= -5
b = -9
the vertex is : (2 , -9)
1, 3, 3, 4, 5, 6, each x is one of each number below