Question

HELP ASAP! PLEASE Solve 1.1(3.4x-2.3)^2=15.5 and write it in ax^2+bx+c=0 form.

Answer 1

Answer:

In the normal ax² + bx + c format, this equation is expressed as:

12.716x² - 17.204x + 9.81 = 0

If we solve for x, it is approximately equal to both 178 and -0.43

Step-by-step explanation:

Let's reformat to ax² + bx + c = 0:

$1.1(3.4x - 2.3)^2 = 15.5\\1.1(11.56x^2 - 15.64x + 5.29) = 15.5\\12.716x^2 - 17.204x + 5.819 = 15.5\\12.716x^2 - 17.204x + 9.81 = 0$

And now let's find the value of x

$1.1(3.4x - 2.3)^2 = 15.5\\(3.4x - 2.3)^2 = 15.5 / 1.1\\(3.4x - 2.3)^2 = 14.09\\3.4x - 2.3 = \sqrt{14.09}\\3.4x = 2.3 \pm \sqrt{14.09}\\x = \frac{2.3 \pm 3.75}{3.4}\\x = (1.78, -0.43)$

Answer 2

Answer:

12.716x^2 -17.204x -9.681=0

Step-by-step explanation: