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aalyn [17]
3 years ago
7

CDEF is a parallelogram. Solve for x. ​

Mathematics
2 answers:
Lana71 [14]3 years ago
7 0

Answer:

x = 12

Step-by-step explanation:

24 = 3x - 12 (opposite sides of a parallelogram are equal)

24 + 12 = 3x

36 = 3x

36/3 = x

12 = x

Paul [167]3 years ago
7 0

Answer:

x=13

Step-by-step explanation:

The parallel sides on a parallelogram are equal, therefore you must find a number that would satisfy the requirement for equality in the sides' length

So lets get started by finding out what number would be 24 after 12 has been subtracted from it.

24+12=36

Now we need to find out how to get 36 from 3x

36/3=13

13.

x is 13.

Now lets check that our answer is right

13x3=36

so far so good.

36-12=24

That checks out.

24=24.

Make sure to rate this answer!

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Using <em>factorization</em> method:

\Rightarrow 8y^{4} (y^{2}+ 10y + 8y + 80)\\\Rightarrow 8y^{4} (y (y+ 10) + 8(y + 10))\\\Rightarrow 8y^{4} (y+ 10)(y + 8))\\\Rightarrow \underline{2y^{2}} \times  4y^{2} \underline{(y+ 10)}(y + 8)) ..... (1)

Now, Making factors of 2y^{4} + 40y^{3} + 200y^{2}

Taking 2y^{2} common:

\Rightarrow 2y^{2} (y^{2}+ 20y+ 100)

Using <em>factorization</em> method:

\Rightarrow 2y^{2} (y^{2}+ 10y+ 10y+ 100)\\\Rightarrow 2y^{2} (y (y+ 10) + 10(y + 10))\\\Rightarrow \underline {2y^{2} (y+ 10)}(y + 10)        ............ (2)

The underlined parts show the Highest Common Factor(HCF).

i.e. <em>HCF</em> is 2y^{2} (y+ 10).

We know the relation between <em>LCM, HCF</em> of the two numbers <em>'p' , 'q'</em> and the <em>numbers</em> themselves as:

HCF \times LCM = p \times q

Using equations <em>(1)</em> and <em>(2)</em>: \Rightarrow 2y^{2} (y+ 10) \times LCM = 2y^{2} \times  4y^{2}(y+ 10)(y + 8) \times 2y^{2} (y+ 10)(y + 10)\\\Rightarrow LCM = 2y^{2} \times  4y^{2}(y+ 10)(y + 8) \times (y + 10)\\\Rightarrow LCM = 8y^{4}(y+ 10)^{2}(y + 8)

Hence, <em>LCM</em> = 8y^{4}(y+ 10)^{2}(y + 8)

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3 years ago
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