(13x² + 5x) + 8x²
= (13 + 8)x² + 5x
= 21x² + 5x
Answer:
y = -6x + 7
Step-by-step explanation:
In this question, we need to find the equation of a line with the given information.
We know that the line passes through (2, -5).
We also know that the line is parallel to the line 6x + y = 6, which means that it has to have the same slope.
To make it simpler to understand, we can change the equation into slope format:
y = -6x + 6
This means that our new line should have a slope of -6.
With the information above, we can plug in our new values to get the y-intercept of our equations, since we don't have that information.
Plug in your slope and coordinates to the y = mx + b equation and solve for b:
-5 = -6(2) + b
-5 = -12 + b
Add 12 to both sides.
7 = b
Our y-intercept would be b.
Now, we can plug in all our information to get our new equation:
y = -6x + 7
Your answer would be y = -6x + 7
If it needs to be a rectangle, then the rectangle with the smallest perimeter for
a given area is the square. He needs 32 feet of fence, and should fence off a
square that's 8 x 8 .
But if he's willing to go to the trouble, the perimeter of a circle with the same area
is even less than the square.
A = (pi) (R²)
R = √(64/pi).
Circumference = (2 pi) (R) = 2 pi √(64/pi) = √(256 pi) = 28.359 (rounded).
That's 11.4% less fence to buy, for a circular run.
But on the other hand, what have you got against the dog ? One of
the two main purposes of a dog run is to give the dog a place to <u>run</u>.
Minimizing the perimeter also minimizes the distance where he can get
up some speed and run in a straight line ... freeing up his hips, clearing
the cobwebs from his brain, smelling the air, keeping his claws nice and
worn down. With the emotional well-being of the dog in mind, I'd expect
you'd want to give him the <u>maximum</u> possible straight route inside the
run, which, unfortunately, also maximizes the amount of fence that Malcolm
has to provide.
But I digress. The math is done. The question is answered.
This case is closed.
16 there is the answer glad to help
