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9966 [12]
3 years ago
12

What is the difference between 2.23 seconds and 3.13 seconds?

Mathematics
2 answers:
boyakko [2]3 years ago
7 0

Answer:

0.9

Step-by-step explanation:

3.13-2.23=0.9

Neko [114]3 years ago
7 0

Answer:

Do you mean subtraction?

Step-by-step explanation:

If so

−  0.9 is your answer

Also bts army?

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Original price of CD: $13.00<br> Discount: 40%
zimovet [89]

Answer:

$7.80

Step-by-step explanation:

Multiply 0.4 (that is 40%) by 13

It would be 5.2

So subtract 5.2 from $13.00

7.8

So the CD price would be $7.80 with a 40% discount

Hope this helps you :)

8 0
3 years ago
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-|j|=-9 <br> can someone please help me solve this equation
forsale [732]
Diide both sides by -1
|j|=9
rememeber if |a|=b, then assume a=b and a=-b

so
j=9 and j=-9

8 0
4 years ago
1) Identify the slope of the given line
adell [148]

ok so here we go:

1) (-6,-2.5),(-4,-3)\ m= -0.25 or  -\frac{1}{4}

2 )y=-0.25x-4 so the answer is (0, -4) or -4

3) y=\frac{3}{2}x+1 m=\frac{3}{2}

4) y=[tex]\frac{3}{2}x+1[tex] so the answer is (0, 1) or 1

8 0
4 years ago
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A rectangle has a height of 4 and a width of x2 + 3x + 2.
Mumz [18]

<u>Question</u>:

A rectangle has a height of 4 and a width of x² + 3x + 2. Express the area of the entire rectangle.

<u>Given:</u>

The height of the rectangle is 4.

The width of the rectangle is x^2+3x+2

We need to determine the area of the entire rectangle.

<u>Area of the entire rectangle:</u>

Let us determine the area of the entire rectangle.

The area of the rectangle can be determined using the formula,

A=height \times width

Substituting height = 4 and width = x^2+3x+2

Thus, we get;

A=4(x^2+3x+2)

Multiplying the terms by 4, we get;

A=4x^2+12x+8

Thus, the area of the entire rectangle is 4 x^{2}+12 x+8

6 0
4 years ago
Toilet paper has been hard to find lately. You go to the store and are surprised to find that they have some toilet paper in sto
statuscvo [17]

Answer:

77

Step-by-step explanation:

Total Volume = 88

Middle Part Volume = 11

Total - Middle = 77

3 0
3 years ago
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