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Ne4ueva [31]
2 years ago
14

Image result for worlds hardest math question

Mathematics
2 answers:
Nina [5.8K]2 years ago
3 0

Answer:

1

Step-by-step explanation:

krok68 [10]2 years ago
3 0

A

Step-by-step explanation:

You might be interested in
Before changes to its management staff, an automobile assembly line operation had a scheduled mean completion time of minutes. T
Sergio [31]

No, we don't have evidence to support that the mean completion time under new management has decreased but we can conclude that it remains at 15.5 minutes.

Given mean of 15.5 minutes , standard deviation of 1.7 minutes, sample size of 90 and sample mean of 15.4 minutes.

We can do the following study for conclusion:

Firstly the null hypothesis is

H_{0}: x=15.5

The alternate hypothesis is

H_{1}: x < 15.5

since the value is less than this is a one tailed test.

Z=x bar-x/d/\sqrt{n}

where x is sample mean and d is standard deviation.

Z=15.4-15.5/1.7/\sqrt{90}

=-0.1/1.7/9.4868

=-0.560

Critical value of Z at 0.1 level of significance

Z=-1.28

We fails to reject the null hypothesis since -0.560>-1,28

Hence we don't have evidence to support that the mean completion time under new management has decreased but we can conclude that it remains at 15.5 minutes.

Learn more about hypothesis at brainly.com/question/11555274

#SPJ4

Question is incomplete. It should include:

mean of 15.5 minutes ,

standard deviation of 1.7 minutes,

sample size of 90

and sample mean of 15.4 minutes.

5 0
1 year ago
Please answer correctly !!!!!!! Will mark brainliest !!!!!!!!!!!!
LUCKY_DIMON [66]

Answer:

=8\sqrt{15}b^{\frac{7}{2}}

Step-by-step explanation:

\sqrt{24b^3}\sqrt{40b^2}\sqrt{b^2}

=\sqrt{40}\sqrt{b^2}\sqrt{b^2}\sqrt{24b^3}

=\sqrt{40}b^2\sqrt{24b^3}

\sqrt{24b^3}

=\sqrt{24}\sqrt{b^3}

=\sqrt{24}b^{\frac{3}{2}}

=\sqrt{24}b^{\frac{3}{2}}\sqrt{40}b^2

=\sqrt{2^3\cdot \:3}b^{\frac{3}{2}}\sqrt{40}b^2

=\sqrt{2^3}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

\sqrt{2^3}

=2^{3\cdot \frac{1}{2}

=2^{3\cdot \frac{1}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3\cdot \:5}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3}\sqrt{5}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}}\sqrt{5}b^2

=\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^2

=\sqrt{3}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^{\frac{3}{2}+2}

2^{\frac{3}{2}+\frac{3}{2}}

=2^3

=2^3\sqrt{3}\sqrt{5}b^{\frac{3}{2}+2}

b^{\frac{3}{2}+2}

=b^{\frac{7}{2}}

=2^3\sqrt{3}\sqrt{5}b^{\frac{7}{2}}

=2^3\sqrt{3\cdot \:5}b^{\frac{7}{2}}

=8\sqrt{15}b^{\frac{7}{2}}

4 0
3 years ago
Helpppppp asapppppopoo
wlad13 [49]
Answer: Choice A

Raising something to the 1/4th power is the same as applying the 4th root to that expression. Raising an expression to the 1/n power is the same as applying the nth root.

Rule:
x^{1/n} = \sqrt[n]{x}
(if the text is too small it basically says x to the (1/n) = square root with a small 'n' all over x)
4 0
2 years ago
What percent represents the part of the model shaded green?
frutty [35]

Answer:

60%

Step-by-step explanation:

Because 3 ÷ 5 = 60% Hope that helps!

8 0
2 years ago
Read 2 more answers
How many multiples of 5 are there between 199 and 1,198? Hint: an = a1 + d(n − 1), where a1 is the first term and d is the commo
GaryK [48]
An=a1+d (n-1)
A1=200 since that's the first term that can be a multiple of 5
N=? That's what we need to find
An=1195 since that's the last multiple of 5 that we can use
D=5
Plug in
1195=200+5 (n-1)
-200 both sides
995=5 (n-1)
Distribute 5 to n-1
995=5n-5
+5 both sides
1000=5n
÷5 both sides
N=200 there are 200 multiples of 5 in between 199 and 1198
4 0
3 years ago
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