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3 years ago

Y=x^2+14x+40 in vertex form by completing the square

1 answer:

4 0

Vertex form of a quadratic is:

y=a(x-h)^2+k (where (h,k) is the vertex of the quadratic)

y=x^2+14x+40

y-40=x^2+14x

y-40+49=x^2+14x+49

y+9=(x+7)^2

y=(x+7)^2-9

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Murrr4er [49]

Answer:

Step-by-step

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explanation:

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2 years ago

Which expression is equivalent to square root 55x^7 y^6/11x^11 y^8? Assume x > 0 and y > 0.

morpeh [17]

The first step for solving this expression is to reduce the fraction with 11.
$\sqrt{ \frac{5 x^{7} y^{6} }{ x^{11} y^{8} } }$
Now reduce the fraction with $x^{7}$ .
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Reduce the fraction one more time with $y^{6}$ .
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To take the root of a fraction,, we must take the root of the numerator and denominator separately. This rule will change the expression to the following:
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Since we cannot simplify this fraction any further,, the final answer is going to be $\frac{ \sqrt{5} }{ x^{2} y}$ .
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3 0

3 years ago

Read 2 more answers

Please anyone can give me it's urgent....

Pavlova-9 [17]

Step-by-step explanation:

From the figure it is clear that:

x+110°=180

x=180-110

x=70

For y:

the left exterior angle of line q is also70.

By the definition of alternate exterior angle:

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2 years ago

9 60° A) x = 18, y=9V6 B) x=9V3, y=9V3 C) x = 18, y=9V3 D) x =9V3, y=9V6

lesantik [10]

Answer:

C. x = 18, y = 9 $\sqrt{3}$

Step-by-step explanation:

In a 30-60-90 triangle,

longer leg = $\sqrt{3}$ (shorter leg)

hypontenuse = 2(shorter leg)

In your case, the shorter leg = 9

therefore, y = 9 $\sqrt{3}$ and x = 2(9) = 18

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3 years ago

Which values for x and y make the statement (x + 3)(y - 11) = 0 true?

Westkost [7]

A,C,and D are all correct

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3 years ago

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