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nadya68 [22]
3 years ago
10

Write in index form 9 x 9 x 4 x 4 x 4 x 9 x 9 x 9

Mathematics
2 answers:
lawyer [7]3 years ago
7 0

Answer:

9^{5} × 4³

Step-by-step explanation:

9 is multiplied by itself 5 times and 4 is multiplied by itself 3 times.

This is expressed in index form as

9^{5} × 4³

Mekhanik [1.2K]3 years ago
6 0

Answer:

9^5×4^3

Step-by-step explanation:

9 has to multiply itself 5 times and 4 has to multiply itself 3 times

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Answer: if it’s median write all numbers and cross till you get to the middle

Step-by-step explanation:

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3 years ago
Tawni watched 3/4 of a movie in 1 1/2 hours. Which is the length of the movie?
ella [17]

Answer:

2 hours.

Step-by-step explanation:

1 1/2 hours is equal to 90 minutes. We can calculate from this that 1/4 of the movie is equal to 30 minutes. To get the answer, we add the missing 1/4 of the movie (equal to 30 minutes) to get a total of 120 minutes, which is equal to two hours.

Good luck! Hope this helped!

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2 years ago
What is 136 - 69 in an explanation I don’t understand how to sub 6 And 9 or regrouping with digits lower than a high number
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3 years ago
Read 2 more answers
. A box in a certain supply room contains four 40-W lightbulbs, five 60-W bulbs, and six 75-W bulbs. Suppose that three bulbs ar
yaroslaw [1]

Answer:

a) 59.34%

b) 44.82%

c) 26.37%

d) 4.19%

Step-by-step explanation:

(a)

There are in total <em>4+5+6 = 15 bulbs</em>. If we want to select 3 randomly there are  K ways of doing this, where K is the<em> combination of 15 elements taken 3 at a time </em>

K=\binom{15}{3}=\frac{15!}{3!(15-3)!}=\frac{15!}{3!12!}=\frac{15.14.13}{6}=455

As there are 9 non 75-W bulbs, by the fundamental rule of counting, there are 6*5*9 = 270 ways of selecting 3 bulbs with exactly two 75-W bulbs.

So, the probability of selecting exactly 2 bulbs of 75 W is

\frac{270}{455}=0.5934=59.34\%

(b)

The probability of selecting three 40-W bulbs is

\frac{4*3*2}{455}=0.0527=5.27\%

The probability of selecting three 60-W bulbs is

\frac{5*4*3}{455}=0.1318=13.18\%

The probability of selecting three 75-W bulbs is

\frac{6*5*4}{455}=0.2637=26.37\%

Since <em>the events are disjoint</em>, the probability of taking 3 bulbs of the same kind is the sum 0.0527+0.1318+0.2637 = 0.4482 = 44.82%

(c)

There are 6*5*4 ways of selecting one bulb of each type, so the probability of selecting 3 bulbs of each type is

\frac{6*5*4}{455}=0.2637=26.37\%

(d)

The probability that it is necessary to examine at least six bulbs until a 75-W bulb is found, <em>supposing there is no replacement</em>, is the same as the probability of taking 5 bulbs one after another without replacement and none of them is 75-W.

As there are 15 bulbs and 9 of them are not 75-W, the probability a non 75-W bulb is \frac{9}{15}=0.6

Since there are no replacement, the probability of taking a second non 75-W bulb is now \frac{8}{14}=0.5714

Following this procedure 5 times, we find the probabilities

\frac{9}{15},\frac{8}{14},\frac{7}{13},\frac{6}{12},\frac{5}{11}

which are

0.6, 0.5714, 0.5384, 0.5, 0.4545

As the events are independent, the probability of choosing 5 non 75-W bulbs is the product

0.6*0.5714*0.5384*0.5*0.4545 = 0.0419 = 4.19%

3 0
3 years ago
Find the difference write the answer in simplest form 11/18 -1/6
nevsk [136]

Answer:

4/9

or

0.4

Step-by-step explanation:

7 0
3 years ago
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