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Vladimir79 [104]
2 years ago
11

Solve and check.

Mathematics
2 answers:
Thepotemich [5.8K]2 years ago
5 0
C/3 = 6 1/7

Multiply 3 to both sides:

C = 6 1/7 * 3

Convert 6 1/7 into an improper fraction:

C = 43/7 * 3

Multiply 3 to the numerator:

C = 129/7

Convert back into a mixed number:

C = 18 3/7
JulijaS [17]2 years ago
5 0
No the answer is 18 3/7 (d) convert 6 1/7 to 43/7 c/3=43/7 cross multiply 7c =129 c= 18 3/7
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Hunter-Best [27]
There isn't any choices given in this problem but I can give you a tip to answer these kinds of problem. When you say independent, it means that the equation cannot be algebraically altered to result to 3x + 4y = 8. So the equation 6x + 8y = 16 is not an independent equation since when you divide each side by 2 it will result to 3x + 4y =8. You get the idea. <span />
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3 years ago
What is the power dissipated by a 5ohm resistor if the current is 4A?​
posledela

Answer:

Answer: First, we use Ohm's law ( V = I × R ), to find the current through the resistor. The voltage across the resistor is V = 9 V. The resistance of the resistor is R = 100 Ω. Then, we can use the power rule ( P = I × V ), to find the power dissipated by the resistor

Step-by-step explanation:

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2 years ago
Two ropes, AD and BD, are tied to a peg on the ground at point D. The other ends of the ropes are tied to points A and B on a fl
BigorU [14]
You have two 30-60-90 triangles, ADC and BDC.

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     1        :  sqrt(3)  :        2

Using triangle ADC, we can find length AC.
Using triangle BDC, we can find length BC.
Then AB = AC - BC

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6 0
2 years ago
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Hey!

The sum of four times a number and -2

Let us take the number as ' x '

( 4x - 2 )

Six times a number and 3

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The sum = ( 4x - 2 ) + ( 6x + 3 )

Hope helps!

6 0
3 years ago
. A special safe lets you choose from 9 symbols for a 3-symbol-long pass code. You may enter a symbol any number of times. How m
Lady_Fox [76]

The question is an illustration of combination and there are 729 potential pass codes available

<h3>How to determine the number of potential pass codes?</h3>

The given parameters are

Symbols available = 9

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