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Vladimir79 [104]

2 years ago

11

Solve and check.

2 answers:

Thepotemich [5.8K]2 years ago

5 0

C/3 = 6 1/7

Multiply 3 to both sides:

C = 6 1/7 * 3

Convert 6 1/7 into an improper fraction:

C = 43/7 * 3

Multiply 3 to the numerator:

C = 129/7

Convert back into a mixed number:

C = 18 3/7

JulijaS [17]2 years ago

5 0

No the answer is 18 3/7 (d) convert 6 1/7 to 43/7 c/3=43/7 cross multiply 7c =129 c= 18 3/7

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2 years ago

Write an algebraic expression that represents 2 less than 18 times a number?<br>

german

Answer:

Step-by-step explanation:

18x-2

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2 years ago

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Mr. rodriquez was on the telephone for 182 minutes. She called 7 friends to invite them to a luncheon. If she spoke to each frie

vitfil [10]

He spoke to each friends for 26 minutes

How I found out : how I found out is that all you have to do it get the total amount which in this question it is going to be 182. And you would need to dive 182 by 7 to find the unit rate (182/7) which is going to equal 26.which means he called each friend for 26 minutes

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2 years ago

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Write the exponential function.

sertanlavr [38]

Answer:

$f(x) = 10*(b)^x$

Step-by-step explanation:

exponential function : $y=a*(b)^x$

where a = y intercept and b = factor ( what you multiply by )

looking at the table the y intercept is at (0,10) so a = 10

so we now have y = 10 * (b)^x

to find the factor we simply plug in one of the ordered pairs.

note that the ordered pair chosen does not effect the outcome

i chose (2,250)

we have y = 10 * (b)^x

(x,y) = (2,250)

250 = 10 * (b)^2

divide both sides by 10

25 = b^2

take the square root of both sides

5 = b

the final equation would be f(x) = 10 * (b)^x

5 0

2 years ago

<img src="https://tex.z-dn.net/?f=Simplify%3A%20%5Cfrac%7B%205%C3%97%2825%29%5E%7Bn%2B1%7D%20-%2025%20%C3%97%20%285%29%5E%7B2n%7

Katen [24]

$\green{\large\underline{\sf{Solution-}}}$

<u>Given expression is </u>

$\rm :\longmapsto\:\dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} }$

can be rewritten as

$\rm \: = \: \dfrac{5 \times { {(5}^{2} )}^{n + 1} - {5}^{2} \times {5}^{2n} }{5 \times {5}^{2n + 3} - {( {5}^{2} )}^{n + 1} }$

We know,

$\purple{\rm :\longmapsto\:\boxed{\tt{ {( {x}^{m} )}^{n} \: = \: {x}^{mn}}}} \\$

And

$\purple{\rm :\longmapsto\:\boxed{\tt{ \: \: {x}^{m} \times {x}^{n} = {x}^{m + n} \: }}} \\$

So, using this identity, we

$\rm \: = \: \dfrac{5 \times {5}^{2n + 2} - {5}^{2n + 2} }{{5}^{2n + 3 + 1} - {5}^{2n + 2} }$

$\rm \: = \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 4} - {5}^{2n + 2} }$

can be further rewritten as

$\rm \: = \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 2 + 2} - {5}^{2n + 2} }$

$\rm \: = \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2} - 1)}$

$\rm \: = \: \dfrac{4}{25 - 1}$

$\rm \: = \: \dfrac{4}{24}$

$\rm \: = \: \dfrac{1}{6}$

<u>Hence, </u>

$\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} } = \frac{1}{6} }}$

4 0

2 years ago