Answer:
see below
Step-by-step explanation:
Dosage= 500 mg
Frequency= twice a day (every 12 hours)
Duration= 10 days
Number of dosage= 10*2= 20
residual drug amount after each dosage= 4.5%
We can build an equation to calculate residual drug amount:
d= 500*(4.5/100)*t= 22.5t, where d- is residual drug, t is number of dosage
After first dose residual drug amount is:
After second dose:
As per the equation, the higher the t, the greater the residual drug amount in the body.
Maximum residual drug will be in the body:
- d= 20*22.5= 450 mg at the end of 10 days
Maximum drug will be in the body right after the last dose, when the amount will be:
75+35+25-75= $60 is the account balance
I think m=2... i think..still learning this subject
Alright, I'm pretty sure I can help.
Let's look at the first answer choice.
7 - 2 (m + 1)
Distribute -2 and add the remaining numbers to get the total for that answer choice.
7 - 2m - 2
Simplify. You get 5 - 2m.
Looks like we found the answer on the first choice!
The Final Answer is 7 - 2 (m + 1)
ANSWER
The discriminant is zero.
The given equation has one real root.
EXPLANATION
The given quadratic equation is:
We rewrite this in the form;
This means that,
a=-2, b= 8, c=-8
The discriminant is given by;
D=b² - 4ac
That is:
Therefore the discriminant is zero.
This tells us that the quadratic equation has one real root.
In order words, the given quadratic equation has a repeated real root.
