D. An inspection report!
Hope this helps!
Answer:
number formatting,
scientific analysis computer programming
Answer and Explanation:
In my view, there is no benefit to having several types of digital storage, but it would be helpful when there is only single SSD format of different sizes, therefore it would be very convenient for an individual to select storage memory and doesn't get frustrated although several choices contribute to uncertainty about what to purchase rather than what is better for the machine. So, only a single centralized memory and the only one that is deemed perfect for your device so far.
(a)...Yeah, then it'll be easier and even more efficient for individuals to have a single standard because there'd be only that standard and then no more ambiguity, although it is quicker or lighter and would have been sufficient to send.
(b)...No, I wouldn't be using the very same piece of hardware if I were considering multiple processing categories because I would require memory interface types for various functions, so those won't all require the very same memory, however, I would like various storage of various sizes and I'm using memory interface categories effectively.
Answer:
Option 1: Finds the position of the largest value in a
Explanation:
Given the codes as follows:
- int[] a = {6, 1, 9, 5, 12, 3};
- int len = a.length;
- int x = 0;
- for (int i = 1; i < len; i++)
- {
- if (a[i] > a[x])
- x = i;
- }
-
- System.out.println(x);
The code is intended to find a largest value in the array, a. The logic is as follows:
- Define a variable to hold an index where largest value positioned. At the first beginning, just presume the largest value is held at index zero, x = 0. (Line 3)
- Next, compare the value location in next index. If the value in the next index is larger, update the index-x to the next index value (Line 4 - 8). Please note the for-loop traverse the array starting from index 1. This is to enable the index-1 value can be compared with index-0 and then followed with index-2, index-3 etc.
- After completion of the for-loop, the final x value will be the index where the largest value is positioned.
- Print the position of the largest value (Line 10)
