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patriot [66]
4 years ago
6

Explain how Deep Packet Inspection works (DPI). How is this technology beneficial to Perimeter Security? Lastly, describe a scen

ario where the use of DPI may be considered a privacy concern.
Computers and Technology
1 answer:
Lera25 [3.4K]4 years ago
7 0

Answer:

Answered below

Explanation:

Deep packet inspection is a kind of data processing that thoroughly inspects data sent over a computer network and acts on it by rerouting, logging or blocking it. Uses of DPI include;

To ensure that data is in the correct format, internet censorship, to check for malicious code, and also eavesdropping.

DPI uses port mirroring and optical splitter to acquire packets for inspection. It combines the functionality of an intrusion detection system and intrusion prevention system with a traditional stateful firewall.

DPI is therefore helpful in perimeter security by keeping unauthorized users out and at the same time protecting authorized users from attack. Privacy concerns have been raised over the inspection of content layers of internet protocols such as in the case of censorship and government regulations and control.

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Earth's current era is the _______ era.
natita [175]
We are in the Cenozoic Era
6 0
4 years ago
Read 2 more answers
Write a full class definition for a class named Player, and containing the following members:
ANEK [815]

// making class

class Player {

// Data members

string name;

int score;

// Name setter

void setName(string str){

this.name = str;

}

// Score setter

void setScore(int num){

this.score = num;

}

// Score getter

int getScore(){

return score;

}

// Name getter

string getName(){

return name;

}

};

8 0
3 years ago
For most general purpose processors, how does the operating system handle the situation when the processor is idle?
erica [24]

Answer:

The operating system handle this system idle situation by using the System Idle Process.

Explanation:

This system idle process constantly keeps the processor occupied means that the processor will not freeze when no processes are in work.When a process is using 12% of the CPU then 88% of the CPU is used by the system idle process.You can see this in the task manager of your windows.

5 0
3 years ago
Python
andreyandreev [35.5K]

Answer:

<h2>1)   </h2>

h = 19  # h is already assigned a positive integer value 19

i = 1  # used to calculate perfect square

q = 0   # stores the sum of the perfect squares

while q < h:  

# this loop executes until value of number of perfect squares is less than h

   q = q + (i*i)  # to calculate the sum of perfect squares

   i = i + 1  # increments i by 1 at every iteration

print(q) # displays the sum of perfect squares

Output:

30

Explanation:

Here we see that the sum of the perfect square is printed in the output i.e. 30. If we want to assign value 4 to q then we should alter the code as  following:  

h = 19

i = 1

sum_of_ps = 0

q=0

while sum_of_ps < h:

   sum_of_ps = sum_of_ps + (i*i)

   q = q + 1

   i = i + 1  

print(q)  

If you want to take input from the user and also display the perfect squares in output you can use the following code:

h = int(input('Enter the value of h: ')) #takes value of h from user

i = 1

sum_of_ps = 0

q=0

while sum_of_ps < h:

   sum_of_ps = sum_of_ps + (i*i)

   print(i*i) #displays the perfect squares of h

   q = q + 1

   i = i + 1    

print(sum_of_ps)   #displays sum of perfect squares

print(q) #displays number of perfect squares whose value is less than h

Output:

1

4

9

16

30

4

<h2>2)</h2>

# k and m are already assigned positive integers 10 and 40

k = 10  

m = 40  

i = 1  # i is initialized to 1

q = 0  # q stores the number of perfect squares between k and m

while i*i < m:  # loop computes perfect square of numbers between k and m

   if i*i > k:          

       q = q + 1  # counts the number of perfect squares

   i = i + 1  #increments the value of i at each iteration

print (q) # prints the no of perfect squares between k and m

If you want to display the perfect squares too use , add print(i*i) statement after if statement  if i*i > k:        

Output:

3

<h2>3)</h2>

def Fibonacci(n):  # method Fibonacci which has an integer parameter n

   if n <= 1:  # if the value of n is less than or equals to 1

       result = n  # stores the value of n into result

   elif n > 1:  # else if the value of n is greater than 1

       result = Fibonacci(n-1) + Fibonacci(n-2)  

# calls Fibonacci method recursively to associate nth value of Fibonacci #sequence with variable result

   return result     #returns the final value stored in result variable

print(Fibonacci(8))

#calls Fibonacci function and passes value 8 to it

Output:

21

8 0
3 years ago
Complete the following method named replaceEvens that receives the parameter numbers which is an array of integers. The method m
Taya2010 [7]

Answer:

Following are the method definition to this question:

public class Neg //defining class Neg

{  

public static void replaceEvens(int[] numbers) //defining a method replaceEvens that accepts array

{

int i; //defining integer variable

for(i = 0 ; i < numbers.length; i++) //defining foop to counts number

{

if(numbers[i]%2 == 0) //defining condition to check number is even  

{

numbers[i] = numbers[i] * -1; //multiply the number by -1

}

}

for(i = 0 ; i < numbers.length; i++) // defining loop print array

{

System.out.print(numbers[i] + " "); //print array

}

}    

public static void main(String[] as)//defining main method  

{

   int[] numbers = {12, 10, 18, 5, 2,22}; //defining array numbers and assign value

   System.out.println("Elements of array: "); //print message

   for(int i = 0 ; i < numbers.length ; i++)  //defining loop to print message

   {

   System.out.print(numbers[i] + " "); //print array

   }

  System.out.println("\n After replaceEvens"); //print message

   replaceEvens(numbers); //calling method replaceEvens

  }

}

Output:

please find the attachment.

Explanation:

  • In the given program a static method replaceEvens is declared, in which array numbers pass as the parameter, inside the for method loop is declared, which counts array number in this loop if block is defined, that check-in array there is an even number.
  • In the condition is true it will multiply the number by -1, and output side the loop it will define another loop to print its value.
  • Inside the main method, a number array is declared, that first prints its value then call the method to print its change value.    

3 0
3 years ago
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