Answer:
3. B. P = 134x + 20y
4. J. (10, 150), I(40, 120), G(60, 100), C(60, 0) and E(10, 0)
5. C. 60 mopeds 100 bicycles
Step-by-step explanation:
3. The given information are;
The number of mopeds the company must produce per month = 10
The number of mopeds the company can produce month = 60
The number of bicycles the company can produce per month = 120
The total sum of the produced mopeds and bicycles ≤ 160
The profit on a moped = $134
The profit on a bicycle = $20
Given that the number of moped produced = x and the number of bicycles produced = y
Therefore, we have;
Profit, P = $134 × x + $20 × y
Which gives;
B. P = 134x + 20y
4) From Desmos, using the following constraints;
x + y ≤ 160
10 ≤ x ≤ 60
0 ≤ y ≤ 120 we have;
The vertices of the constraint for the feasible region are;
J. (10, 150), I(40, 120), G(60, 100), C(60, 0) and E(10, 0)
5) We note that since the profit from each moped is more than the profit from the sale of each bicycle, the maximum possible number of moped should be produced, while the rest should be used to produce bicycles
Therefore, given that from the vertices, the maximum possible number of moped = 60, the number of bicycles to be produced should be 160 - 60 = 100 bicycles
Which gives;
C. 60 mopeds 100 bicycles.
