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ikadub [295]
3 years ago
7

You have also set up a card game in which a player picks a card from a standard deck of 52 cards. The player wins if these two e

vents occur together: E1, in which the card drawn is a black card, and E2, in which the card drawn is a numbered card, 2 through 10.What is the probability of getting a black card and a numbered card? Calculate the probabilities P(E1) and P(E2) as fractions.
Mathematics
1 answer:
Alenkinab [10]3 years ago
5 0

First, let's count:

there are 26 possible outcomes for E1 (black card)

there are 4x9 = 36 possible outcomes for E2, to pick a numbered card (any color)

there are 2x9 =18 possible outcomes for E1 (black) AND E2 (numbered, spade + clower)

the probability of E1 AND E2 is the ratio of the count of possible outcomes for E1 + E2 and the count of all possible outcomes (52 choices to pick a card from the deck):

P(E1 and E2) = 18/52 (34.6%)

And as asked:

P(E1) = 26/52 = 1/2 (50%)

P(E2) = 36/52 = 9/13 (69.2%)

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Answer:

\% Below\ 50 = 88 \%

\% 43\ or\ more = 17 \%

Step-by-step explanation:

Given

Total = 200

<em>The attachment presents the table properly</em>

Solving (a): Percentage of those who play for less than 50 hours weekly

To do this, we simply consider the frequency of students that fall within:

1.0 - 7.9, 8.0 - 14.9,......,43.0 - 49.9

Their frequency is:

Frequency = 21 + 37 + 40 + 27 + 23 + 18 + 10

Frequency = 176

The percentage is then calculated as:

\% Below\ 50 = \frac{Frequency}{Total} * 100\%

\% Below\ 50 = \frac{176}{200} * 100\%

\% Below\ 50 = \frac{176* 100}{200} \%

\% Below\ 50 = \frac{176* 1}{2} \%

\% Below\ 50 = \frac{176}{2} \%

\% Below\ 50 = 88 \%

Solving (b): Percentage of those who play for 43 or more hours weekly

To do this, we simply consider the frequency of students that fall within:

43.0 - 49.9,......,64.0 - 70.9

Their frequency is:

Frequency = 10 + 7 + 5+12

Frequency = 34

The percentage is then calculated as:

\% 43\ or\ more = \frac{Frequency}{Total} * 100\%

\% 43\ or\ more = \frac{34}{200} * 100\%

\% 43\ or\ more = \frac{34* 100}{200} \%

\% 43\ or\ more = \frac{34* 1}{2} \%

\% 43\ or\ more = \frac{34}{2} \%

\% 43\ or\ more = 17 \%

7 0
3 years ago
Urgent please
Natasha2012 [34]

Boys : Girls = 3 : 5


3 + 5 = 8 parts


<u>Find 1 part:</u>

8 parts = 40 students

1 part = 40 ÷ 8 = 5 students


<u>Find number of boys and girls:</u>

3 parts = 3 x 5 = 15 girls

5 parts = 5 x 5 = 25 boys


Original Number of students = 15 : 25


<u>Find new ratio:</u>

New Ratio = 15 + 3 : 25 - 1 = 18 : 24 = 3 : 4


Answer: 3 : 4

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