$25.60
20%=.2
since it's 20% OFF, you want to get rid of .2 of the 32.
so 1-.2=.8
and .8 x 32 = 25.60
Step-by-step explanation:
Firstly, we have to find m∠J.
Since all the angles of a Δ equal 180°, angles J, L, and K should have a sum of 180°.
So,
m∠J + m∠L + m∠K = 180°
The diagram shows us that ∠L = 49° and ∠K = 90°, so we plug in those numbers in the equation.
m∠J + 49° + 90° = 180°
Then we simplify
m∠J + 139° = 180°
Subtract 139° to both sides
∠J = 41
Now the other angles.
Since ΔJKL ~ ΔRST, then ∠J ≅ ∠R, ∠K ≅ ∠S, and ∠L ≅ ∠T
Meaning, m∠J = m∠R, m∠K = m∠S, and m∠L = m∠T
Since we know m∠J = 41°, m∠K = 90°, and m∠L = 49° we could plug those in so...
41° = m∠R , 90° = m∠S , and 49° = m∠T
y-intercept: (0, 1)
Line of symmetry calculation: x = -b/2a = -(-2)/2(2) = 0.5
Line of symmetry: x = 0.5
Open UP or DOWN: Opens UP
Min or Max: Min
Vertex: (0.5, 0.5)
Domain: {x|x ∈ ℝ}
Range: {y|y ≥ 1/2}
I believe that you would just multiply 2.35*5 and that would be your answer.
=11.75
Now, there are 360° in a circle, how many times does 360° go into 1860°?
well, let's check that,
now, this is a negative angle, so it's going
clockwise, like a clock moves, so it goes around the circle clockwise 5 times fully, and then it goes 1/6 extra.
well, we know 360° is in a circle, how many degrees in 1/6 of 360°? well, is just 360/6 or their product, and that's just 60°.
so -1860, is an angle that goes clockwise, negative, 5 times fully, then goes an extra 60° passed.
5 times fully will land you back at the 0 location, if you move further down 60° clockwise, that'll land you on the IV quadrant, with an angle of -60°.
therefore, the csc(-1860°) is the same as the angle of csc(-60°), which is the same as the csc(360° - 60°) or csc(300°).